Maths Formulae Transforms Fourier Transform Pairs

Fourier Transform Pairs – Standard Function Equivalents

Review common Fourier transform pairs that map time-domain functions to their frequency-domain counterparts.
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Definition of Fourier Transform Pairs

A Fourier Transform pair refers to a function in the time or spatial domain and its corresponding representation in the frequency domain. The Fourier Transform, denoted by `F(s)` or `\mathcal{F}\{f(x)\}`, decomposes a function into its constituent frequencies. Pre-computed pairs for common functions serve as reference identities, allowing for the transformation of complex signals and the solution of differential equations without performing the integration manually.

\[ F(s) = \int_{-\infty}^{\infty} f(x)e^{-2\pi i sx}dx \]
Fourier Transform Definition

The relationship is often written using a double-arrow notation to indicate the transform pair.

\[ f(x) \iff F(s) \]
Transform Pair Notation
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Common Fourier Transform Pairs

Time/Spatial Domain Function, f(x)Frequency Domain Function, F(s)
`\delta(x)` (Dirac Delta)`1`
`1` (Constant)`\delta(s)`
`e^{-a|x|}` (Exponential Decay)`\frac{2a}{a^2 + 4\pi^2 s^2}`
`e^{-x^2/a^2}` (Gaussian)`a\sqrt{\pi}e^{-\pi^2 a^2 s^2}`
`\cos(ax)``\frac{1}{2}[\delta(s - a/2\pi) + \delta(s + a/2\pi)]`
`\sin(ax)``\frac{1}{2i}[\delta(s - a/2\pi) - \delta(s + a/2\pi)]`
`\text{sinc}(x) = \frac{\sin(\pi x)}{\pi x}`Rectangular Pulse (`\text{rect}(s)`)
Rectangular Pulse (`\text{rect}(x)`)`\text{sinc}(s)`
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Visualizing a Transform Pair

f(t) F(ω) rect(t) sinc(ωT/2π) δ(t) 2π (constant) e^(−t²) √π · e^(−ω²/4) Key Fourier Transform pairs
Fourier Transform Pairs: rect ↔ sinc, impulse ↔ constant, Gaussian ↔ Gaussian

A common visualization shows a function in the time domain (x-axis) and its corresponding representation in the frequency domain (s-axis). For instance, a pure cosine wave in the time domain, which oscillates indefinitely, is represented in the frequency domain by two infinitely sharp peaks (Dirac delta functions). These peaks are located at the positive and negative frequencies that constitute the wave.

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Properties of the Fourier Transform

PropertyTime DomainFrequency Domain
Linearity`af(x) + bg(x)``aF(s) + bG(s)`
Time Scaling`f(ax)``\frac{1}{|a|}F\left(\frac{s}{a}\right)`
Time Shifting`f(x-a)``e^{-2\pi ias}F(s)`
Frequency Shifting (Modulation)`e^{2\pi iax}f(x)``F(s-a)`
Differentiation`\frac{d^n}{dx^n} f(x)``(2\pi is)^n F(s)`
Convolution`(f * g)(x)``F(s)G(s)`
Multiplication`f(x)g(x)``(F * G)(s)`
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Proof of the Time-Shifting Property

Let's prove the time-shifting property, which states that a shift in the time domain corresponds to a phase shift in the frequency domain.

\[ \mathcal{F}\{f(x-a)\} = e^{-2\pi ias}F(s) \]
Time-Shifting Property

Step 1: Start with the definition of the Fourier Transform applied to the shifted function `f(x-a)`.

\[ \mathcal{F}\{f(x-a)\} = \int_{-\infty}^{\infty} f(x-a)e^{-2\pi i sx}dx \]

Step 2: Use a change of variables. Let `u = x - a`, which implies `x = u + a` and `du = dx`. The limits of integration remain unchanged.

\[ \int_{-\infty}^{\infty} f(u)e^{-2\pi i s(u+a)}du \]

Step 3: Separate the exponential term using the property `e^{A+B} = e^A e^B`.

\[ \int_{-\infty}^{\infty} f(u)e^{-2\pi i su}e^{-2\pi i sa}du \]

Step 4: The term `e^{-2\pi i sa}` is a constant with respect to the integration variable `u`, so it can be factored out of the integral.

\[ e^{-2\pi i sa} \int_{-\infty}^{\infty} f(u)e^{-2\pi i su}du \]

Step 5: Recognize that the remaining integral is the definition of the Fourier Transform of `f(u)`, which is `F(s)`. This completes the proof.

\[ \mathcal{F}\{f(x-a)\} = e^{-2\pi ias}F(s) \]
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Worked Example

Using the transform pair for the Gaussian function `e^{-x^2/a^2}`, find the Fourier Transform of `g(x) = e^{-x^2/16}`.
  1. The standard Fourier Transform pair for a Gaussian function is `e^{-x^2/a^2} \iff a\sqrt{\pi}e^{-\pi^2 a^2 s^2}`.
  2. Compare the given function `g(x) = e^{-x^2/16}` with the standard form `e^{-x^2/a^2}`.
  3. By comparison, we can see that `a^2 = 16`, which means `a = 4`.
  4. Substitute `a = 4` into the frequency domain expression `a\sqrt{\pi}e^{-\pi^2 a^2 s^2}`.
  5. The transform is `4\sqrt{\pi}e^{-\pi^2 (4^2) s^2} = 4\sqrt{\pi}e^{-16\pi^2 s^2}`.
The Fourier Transform of `e^{-x^2/16}` is `G(s) = 4\sqrt{\pi}e^{-16\pi^2 s^2}`.
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Applications

Fourier Transform pairs are fundamental tools in many scientific and engineering disciplines for analyzing signals and systems in the frequency domain.

  • Signal and Audio Processing: Used for filtering, modulation, and spectral analysis. Audio equalizers work by manipulating the Fourier transform of a sound signal.
  • Image Processing: Essential for image compression (like JPEG), filtering (sharpening or blurring), and pattern recognition.
  • Telecommunications: Used to design and analyze modulation schemes like AM and FM, allowing multiple signals to be transmitted over the same channel at different carrier frequencies.
  • Physics and Quantum Mechanics: Used to solve wave equations and other partial differential equations. In quantum mechanics, it relates the position and momentum representations of a particle's wave function.
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Real-World Examples

A radio station broadcasts at a carrier frequency of 95.5 MHz. The signal is modulated by a simple tone of 1 kHz, modeled by `f(t) = \cos(2000\pi t)`. Using the frequency shifting property `e^{2\pi iax}f(x) \iff F(s-a)`, determine the frequencies present in the broadcast signal.
  1. First, find the transform of the tone `f(t)`. Using the cosine pair with `a_0 = 2000\pi`, `F(s) = \frac{1}{2}[\delta(s - 1000) + \delta(s + 1000)]`.
  2. The carrier wave is `e^{2\pi i a t}` where `a = 95.5 \times 10^6` Hz.
  3. The broadcast signal is `f(t)e^{2\pi i a t}`. The frequency shifting property states its transform is `F(s-a)`.
  4. Substitute `s` with `s-a`: `G(s) = \frac{1}{2}[\delta(s-a - 1000) + \delta(s-a + 1000)]`.
  5. The frequencies are at `s = a+1000` and `s = a-1000`.
  6. Calculate the frequencies: `95,500,000 + 1000 = 95,501,000` Hz and `95,500,000 - 1000 = 95,499,000` Hz.
The broadcast signal contains two main frequencies: 95.501 MHz and 95.499 MHz.
An engineer designs a simple low-pass filter with an impulse response of `h(t) = e^{-5|t|}`. What is its frequency response `H(s)`?
  1. The impulse response is `h(t) = e^{-a|t|}` with `a=5`.
  2. The relevant Fourier Transform pair is `e^{-a|x|} \iff \frac{2a}{a^2 + 4\pi^2 s^2}`.
  3. Substitute `a=5` into the frequency domain formula.
  4. `H(s) = \frac{2(5)}{5^2 + 4\pi^2 s^2}`.
  5. Simplify the expression.
The frequency response of the filter is `H(s) = \frac{10}{25 + 4\pi^2 s^2}`. This function has a large value for `s` near 0 and decays as frequency `s` increases, confirming it is a low-pass filter.
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Real-World Scenarios

pixel data DCT freq coeff JPEG: rect block → DCT discard high-freq → compress
JPEG Image Compression
JPEG uses the Discrete Cosine Transform on 8×8 pixel blocks. The rect→sinc pair explains why keeping only low-frequency DCT coefficients recovers most visual information — high-frequency coefficients can be discarded with minimal perceptual impact.
time domain frequency sinc spectrum rect(t) ↔ sinc(f) shorter pulse = wider BW
Pulse Radar Design
A radar pulse is a rectangular function in time — its Fourier Transform is a sinc in frequency. The rect↔sinc pair tells designers: shorter pulse = wider bandwidth = better range resolution.
δ(t) impulse all frequencies F(ω) = 1 δ(t) ↔ 1 (all freqs) impulse = perfect test signal excites entire spectrum equally
System Impulse Testing
The δ(t)↔1 pair explains why impulse testing is universal in engineering: a sharp impulse excites all frequencies equally, letting engineers measure a system's complete frequency response in one test.
Medical Imaging (MRI)

Magnetic Resonance Imaging (MRI) machines collect data in the frequency domain, known as k-space. This raw data represents the Fourier transform of the actual patient anatomy. Powerful computers then perform a 2D or 3D inverse Fourier transform on this k-space data to reconstruct the detailed cross-sectional images used by doctors for diagnosis.

Audio Equalization

When you adjust the bass or treble on a stereo system, you are manipulating the frequency content of the audio signal. The equalizer is essentially a set of filters that boost or cut specific frequency bands. The entire process relies on the principle that any complex sound can be broken down into a sum of simple sine waves, which is the core idea of the Fourier Transform.

Vibration Analysis

Engineers analyze vibrations in structures like bridges or aircraft wings to ensure their safety and stability. Sensors measure the structure's movement over time. By taking the Fourier Transform of this time-domain data, engineers can identify the structure's resonant frequencies—the specific frequencies at which it vibrates most intensely. This is crucial for avoiding catastrophic failure due to resonance.

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Types of Fourier Transforms

The concept of the Fourier Transform adapts to different types of signals. The pairs listed here are for the standard continuous Fourier Transform. Other related transforms are used for periodic or discrete signals.

Transform TypeInput Signal CharacteristicsOutput Spectrum Characteristics
Fourier Transform (FT)Continuous and aperiodicContinuous and aperiodic
Fourier Series (FS)Continuous and periodicDiscrete and aperiodic
Discrete-Time Fourier Transform (DTFT)Discrete and aperiodicContinuous and periodic
Discrete Fourier Transform (DFT)Discrete and periodicDiscrete and periodic

The Discrete Fourier Transform (DFT) is the most important for practical applications, as it is the form that can be computed by a computer, typically using the highly efficient Fast Fourier Transform (FFT) algorithm.

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Common Mistakes

⚠️ Inconsistent Definitions: Different fields use different conventions for the Fourier Transform, primarily in the placement of the `2π` term (e.g., using angular frequency `ω = 2πs` vs. ordinary frequency `s`). Using a transform pair from a physics textbook with a formula from an engineering textbook can lead to scaling errors. Always check the definition being used.
💡 Confusing Duality: The transform has a beautiful symmetry (duality), where the shape of a function in the time domain determines the shape in the frequency domain and vice-versa (e.g., a rect becomes a sinc, and a sinc becomes a rect). However, it's easy to forget the scaling factors and sign changes that may occur when applying the duality property.
⚠️ Misinterpreting the Dirac Delta Function: The `δ` function in frequency domain pairs (like for `cos(ax)`) represents an infinitely narrow, infinitely tall spike at a specific frequency. It is not a standard function and should be treated as a spectral line representing a pure tone, not a value that can be simply plugged into other equations.
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Study Strategy

1 📚 Grasp the Core Concepts
  • Review the 'Definition of Fourier Transform Pairs' to understand the symmetrical relationship between the time and frequency domains.
  • Use the 'Visualizing a Transform Pair' section to build intuition for how a function's shape changes between domains (e.g., a wide pulse in time is a narrow pulse in frequency).
  • Clarify the concept of duality by studying how the forms of the transform pairs can be interchanged, as explained in the 'Properties of the Fourier Transform' section.
  • Distinguish between the different 'Types of Fourier Transforms' (e.g., Continuous-Time vs. Discrete-Time) to know when to apply the standard pair formulas.
2 🧠 Commit Key Pairs to Memory
  • Create flashcards for the 5-7 most fundamental pairs listed under 'Common Fourier Transform Pairs', such as the rectangular pulse ↔ sinc function.
  • Memorize the transform of the Gaussian function, noting the unique property that it transforms into another Gaussian.
  • Learn the transform pair for the Dirac delta function (δ(t)) ↔ constant (1), as it is fundamental to sampling theory.
  • Practice recalling the transform of an exponential decay (e⁻ᵃᵗu(t)) and its corresponding rational function in the frequency domain.
3 ✍️ Apply Properties and Solve
  • Follow the 'Worked Example' step-by-step, then attempt to solve it again from scratch without looking at the solution.
  • Use the time-shifting property, whose proof is provided, to find the transform of a function that is not centered at the origin.
  • Solve practice problems that require using linearity and scaling properties to find the transform of a composite signal (e.g., 5rect(t) + 2rect(t-1)).
  • Review the 'Common Mistakes' section to avoid frequent errors, such as confusing angular frequency (ω) with frequency (f).
4 🌐 Link Theory to Application
  • Read the 'Applications' section and explain how a specific transform pair (e.g., rect/sinc) is used in signal filtering.
  • Analyze one of the 'Real-World Scenarios', like audio equalization, and identify which input signals correspond to which common transform pairs.
  • Connect the 'Real-World Examples' of MRI to the concept of frequency analysis, describing how spatial information is encoded in the frequency domain.
  • Explore how 'Related Transforms' like the Laplace Transform are used in control systems when signals are not absolutely integrable, unlike standard Fourier cases.
Mastering these pairs transforms complex signals into simple frequencies, unlocking a deeper understanding of the world around you.

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