Maths Formulae Statistics Combinations

Combinations – Selecting Items Without Order

Learn combination formulas to find how many ways items can be selected without regard to order.
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Definition

A combination is a mathematical technique for determining the number of possible arrangements in a collection of items where the order of the selection does not matter. It answers the question, "In how many ways can I choose r items from a set of n items?"

For example, if you are choosing 3 toppings for a pizza from a list of 10, the order in which you choose them (e.g., pepperoni then mushrooms then onions) results in the same pizza as choosing them in a different order (e.g., mushrooms then onions then pepperoni). Combinations count these as a single outcome.

SymbolMeaning
nThe total number of distinct items in the set.
rThe number of items to choose from the set.
C(n,r) or \( \binom{n}{r} \)The number of combinations of 'n choose r'.
!Factorial, the product of all positive integers up to that number (e.g., 4! = 4 × 3 × 2 × 1 = 24).
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Key Formulas

\[ C(n,r) = \binom{n}{r} = \frac{n!}{r!(n-r)!} \]
Standard Combination Formula

This formula calculates the number of ways to choose r items from a set of n items, where order is not important. It is valid for \( 0 \leq r \leq n \).

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Conceptual Diagram

Choose 3 from 5 — C(5,3) = 10 ways A B C D E { A B C } { A B D } { A C E } … 10 combinations total C(n,r) = n! / (r!(n−r)!) Order does NOT matter
Combinations C(n,r): select r items from n — order irrelevant, so ABC = ACB = BCA

Imagine a large circle containing 'n' distinct dots, representing the total set of items. A combination is visualized by drawing a smaller circle that encloses 'r' of these dots. There are many such smaller circles possible. The combination formula C(n,r) counts how many unique groups of 'r' dots can be formed, regardless of their position within the smaller circle, emphasizing that order does not matter.

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Properties

\[ \binom{n}{r} = \binom{n}{n-r} \]
Symmetry Property

The number of ways to choose r items from n is the same as the number of ways to leave (n-r) items behind.

\[ \binom{n}{0} = \binom{n}{n} = 1 \]
Boundary Cases

There is only one way to choose zero items (the empty set) and only one way to choose all n items.

\[ \binom{n}{1} = \binom{n}{n-1} = n \]
Single Selection

There are n ways to choose one item from a set of n.

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Proof of the Combination Formula

The combination formula can be derived from the permutation formula. A permutation is an ordered arrangement.

1. Start with the number of ways to arrange r items chosen from n, which is the permutation formula P(n,r).

\[ P(n,r) = \frac{n!}{(n-r)!} \]

2. This counts every different ordering as a separate outcome. For any given set of r items, there are r! ways to arrange them.

3. Since combinations do not care about order, we must divide the total number of permutations by the number of arrangements (r!) for each set of r items to eliminate the overcounting.

\[ C(n,r) = \frac{P(n,r)}{r!} \]

4. Substituting the expression for P(n,r) gives the final formula for combinations:

\[ C(n,r) = \frac{n! / (n-r)!}{r!} = \frac{n!}{r!(n-r)!} \]
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Worked Example

Calculate the number of combinations when choosing 3 items from a set of 5, i.e., find C(5, 3).
  1. Identify the total number of items, n=5.
  2. Identify the number of items to choose, r=3.
  3. Apply the combination formula: \( C(n,r) = \frac{n!}{r!(n-r)!} \).
  4. Substitute the values: \( C(5,3) = \frac{5!}{3!(5-3)!} = \frac{5!}{3!2!} \).
  5. Calculate the factorials: \( 5! = 120 \), \( 3! = 6 \), \( 2! = 2 \).
  6. Compute the result: \( C(5,3) = \frac{120}{6 \times 2} = \frac{120}{12} = 10 \).
There are 10 possible combinations.
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Try It

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Applications

Probability and Statistics: Combinations are fundamental to calculating probabilities. For example, they are used to determine the odds of winning a lottery, the likelihood of being dealt a certain hand in card games (like a full house in poker), and in designing experiments by selecting random samples from a population.

Computer Science: In algorithm design, combinations are used in problems related to selecting subsets, such as finding all possible subsets of a given size. They are also used in cryptography and network security for generating keys and analyzing protocol security.

Genetics: Biologists use combinations to predict the possible genetic makeup of offspring. When parents have different alleles for a trait, combinations can calculate the number of ways these alleles can be passed down.

Quality Control: In manufacturing, a quality control engineer might select a random sample of items from a production batch to test for defects. Combinations are used to determine the number of ways a sample of a certain size can be chosen for inspection.

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Real-World Examples

A school needs to form a student council committee of 4 students from a group of 25 interested candidates. How many different committees can be formed?
  1. Here, n=25 (total candidates) and r=4 (committee size).
  2. Use the combination formula: \( C(25, 4) = \frac{25!}{4!(25-4)!} = \frac{25!}{4!21!} \).
  3. Simplify the expression: \( \frac{25 \times 24 \times 23 \times 22}{4 \times 3 \times 2 \times 1} \).
  4. Calculate the result: \( 25 \times 2 \times 23 \times 11 = 12,650 \).
There are 12,650 different ways to form the committee.
In a standard deck of 52 playing cards, how many different 5-card hands are possible?
  1. The total number of items is n=52, and we are choosing r=5.
  2. Apply the formula: \( C(52, 5) = \frac{52!}{5!(52-5)!} = \frac{52!}{5!47!} \).
  3. Simplify: \( \frac{52 \times 51 \times 50 \times 49 \times 48}{5 \times 4 \times 3 \times 2 \times 1} \).
  4. Calculate the final number: \( 2,598,960 \).
There are 2,598,960 possible 5-card hands.
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Real-World Scenarios

1 2 3 4 5 6 Lottery: Pick 6 from 49 C(49,6) = 13,983,816 1 in 14 million chance Order doesn't matter
Lottery Odds
Picking 6 numbers from 49 — order doesn't matter — gives C(49,6) = 13,983,816 possible combinations, making the jackpot odds roughly 1 in 14 million.
SET MENU Starters (3 of 6): Mains (1 of 8): Desserts (2 of 5): C(6,3)=20 C(8,1)=8 C(5,2)=10 Total meals = 20×8×10 = 1,600
Menu Design
A restaurant with 3 courses and C(6,3)×C(8,1)×C(5,2) choices gives 1,600 distinct meal combinations — useful for planning kitchen stock and variety.
A B C D E Choose 3 players from 5: ABC ABD ABE ACD ACE ADE BCD BCE BDE CDE C(5,3) = 10 teams
Team Selection
A coach choosing 3 players from 5 candidates has C(5,3)=10 possible squads. This scales to C(23,11) = 1,352,078 possible football starting XIs from a 23-man squad.

Choosing a Project Team

A manager needs to select a team of 4 engineers from her department of 15. The combination formula helps determine how many unique team compositions are possible, as the order of selection is irrelevant to the final team.

Restaurant Menu

A restaurant offers a 'build your own' salad with 20 available ingredients, and customers can choose any 5. Combinations are used to calculate the total number of different salad varieties the restaurant can offer.

Lottery Drawings

State and national lotteries involve drawing a set of numbers from a larger pool. The number of possible winning combinations is calculated using C(n,r), which is why the odds of winning are typically very low.

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Types and Classification

Combinations are a part of a broader field called combinatorics. It's crucial to distinguish them from related concepts based on whether order matters and if repetition is allowed.

ConceptOrder Matters?Repetition Allowed?Formula
CombinationNoNo\( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
PermutationYesNo\( P(n,r) = \frac{n!}{(n-r)!} \)
Combination with RepetitionNoYes\( \binom{n+r-1}{r} \)
Permutation with RepetitionYesYes\( n^r \)
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Common Mistakes

⚠️ Confusing Combinations with Permutations: This is the most frequent error. Always ask: 'Does the order of selection matter?' If it doesn't (e.g., selecting a committee), use combinations. If it does (e.g., assigning specific roles like President and VP), use permutations.
💡 Incorrectly Canceling Factorials: Be careful when simplifying the formula. You cannot cancel terms like \( \frac{n!}{r!} \) to get \( (n-r)! \). Always expand the factorials first. For example, \( \frac{10!}{7!} = \frac{10 \times 9 \times 8 \times 7!}{7!} = 10 \times 9 \times 8 \).
💡 Forgetting that \( 0! = 1 \): This is a mathematical convention that is essential for boundary cases. Forgetting this leads to incorrect answers for C(n, n) and C(n, 0), which should both equal 1.
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Study Strategy

1 📖 Grasp the Core Concept
  • Focus on the definition: Combinations are selections where order does not matter.
  • Use the conceptual diagram to visually contrast Combinations (groups) with Permutations (arrangements).
  • Study the key properties, such as C(n, k) = C(n, n-k), to understand the symmetries.
  • Clearly identify 'n' (the total set of items) and 'k' (the subset you are choosing) in any problem statement.
2 🧠 Commit the Formula to Memory
  • Write out the primary formula, C(n, k) = n! / (k! * (n-k)!), multiple times until it is memorized.
  • Verbally explain each part of the formula, especially why you divide by k! to remove ordered arrangements.
  • Review the proof of the formula to build a deeper understanding of its logical derivation from permutations.
  • Practice calculating the factorial component (n!) for various numbers to improve speed and accuracy.
3 ✍️ Practice with Guided Problems
  • Follow the provided 'Worked Example' step-by-step, then try to solve it yourself without looking.
  • Solve practice problems, focusing first on correctly identifying 'n' and 'k' before calculating.
  • Review the 'Common Mistakes' section to actively avoid errors like mixing up combinations and permutations.
  • Work through problems that involve related formulas, such as calculating combinations with repetition if covered.
4 🌍 Apply to Real-World Scenarios
  • Analyze the 'Real-World Scenarios' like lottery odds or forming a committee, and set up the formula for each.
  • Create your own simple scenarios, such as choosing pizza toppings or selecting a team from a group of friends.
  • Explore the 'Applications' section to understand how combinations are used in fields like probability and data analysis.
  • Attempt multi-step problems that require using the combinations formula as part of a larger solution.
By systematically building from concepts to application, you can master combinations and confidently solve selection problems.

Frequently Asked Questions

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