Maths Formulae Algebra Arithmetic Progression

Arithmetic Progression Formulas – nth Term and Sum

Explore arithmetic progression formulas including nth term, common difference, and sum of n terms. Core concept in algeb...
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Definition of an Arithmetic Progression

An arithmetic progression (AP), also known as an arithmetic sequence, is a sequence of numbers such that the difference between consecutive terms is constant. This constant difference is called the common difference, denoted by d. The sequence follows a pattern of linear growth or decay.

Key Terms:

  • First Term (a₁): The starting number of the sequence.
  • Common Difference (d): The constant value added to each term to get the next term. It can be positive, negative, or zero.
  • nth Term (aₙ): The term at the nth position in the sequence.
\[ a_n = a_1 + (n-1)d \]
General Term Formula
\[ d = a_{n+1} - a_n \]
Common Difference
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Key Formulas

\[ a_n = a_1 + (n-1)d \]
Formula for the nth Term
\[ S_n = \frac{n}{2}[2a_1 + (n-1)d] \]
Sum of the First n Terms
\[ S_n = \frac{n}{2}(a_1 + a_n) \]
Alternative Sum Formula
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Visualizing an Arithmetic Progression

n aₙ a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11 a12 +d aₙ = a₁ + (n−1)d Sₙ = n/2·(a₁+aₙ)
Arithmetic progression: terms increase by constant difference d. Points lie on a straight line (linear growth). aₙ=a₁+(n−1)d; sum Sₙ=n/2·(a₁+aₙ).

An arithmetic progression can be visualized on a 2D graph by plotting the term value (aₙ) on the y-axis against the term number (n) on the x-axis. The resulting points (1, a₁), (2, a₂), (3, a₃), ... will always lie on a straight line. The slope of this line is equal to the common difference (d), and the y-intercept is a₁ - d.

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Properties of Arithmetic Progressions

Linear Growth: The relationship between the term number (n) and the term value (aₙ) is linear. This property makes APs useful for modeling any situation involving a constant rate of change.

Arithmetic Mean Property: Any term in an arithmetic progression (except the first and last) is the arithmetic mean of its two neighboring terms. This is useful for finding missing terms.

\[ a_k = \frac{a_{k-1} + a_{k+1}}{2} \]
Arithmetic Mean Property

Constant Operations: If you add, subtract, multiply, or divide every term of an AP by a constant non-zero number, the resulting sequence is also an AP.

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Proof of the Sum Formula

We can derive the formula for the sum of the first n terms, Sₙ, by writing the sum in two ways: forwards and backwards.

First, write the sum in its standard order:

\[ S_n = a_1 + (a_1+d) + (a_1+2d) + \cdots + (a_n-d) + a_n \]

Next, write the sum in reverse order:

\[ S_n = a_n + (a_n-d) + (a_n-2d) + \cdots + (a_1+d) + a_1 \]

Now, add the two equations together, term by term:

\[ 2S_n = (a_1+a_n) + (a_1+d+a_n-d) + \cdots + (a_n+a_1) \]

Each pair of terms sums to (a₁ + aₙ). Since there are n terms in the sequence, there are n such pairs.

\[ 2S_n = n(a_1 + a_n) \]

Finally, divide by 2 to solve for Sₙ.

\[ S_n = \frac{n}{2}(a_1 + a_n) \]
Derived Sum Formula
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Worked Example

For the arithmetic progression 5, 9, 13, 17, ..., find the 15th term (a₁₅) and the sum of the first 15 terms (S₁₅).
  1. Identify the first term a₁ and the common difference d. Here, a₁ = 5. The common difference is d = 9 - 5 = 4.
  2. Use the formula aₙ = a₁ + (n-1)d to find a₁₅. Substitute n=15, a₁=5, and d=4: a₁₅ = 5 + (15-1) * 4 = 5 + 14 * 4 = 5 + 56 = 61.
  3. Use the formula Sₙ = n/2 * (a₁ + aₙ) to find S₁₅. Substitute n=15, a₁=5, and a₁₅=61: S₁₅ = 15/2 * (5 + 61) = 7.5 * 66 = 495.
The 15th term is 61, and the sum of the first 15 terms is 495.
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Try It

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Applications

💰 Financial Planning & Investment

Financial advisors use arithmetic progressions for calculating loan payments with simple interest, designing savings plans with regular contributions, and analyzing investment returns that increase by a fixed amount periodically.

🏭 Manufacturing & Production

Engineers apply arithmetic progressions for production line scheduling, where output increases by a constant amount over time. It's also used in inventory management and quality control sampling at regular intervals.

🌡️ Scientific Research & Data Analysis

Scientists use arithmetic progressions to establish measurement intervals, calibrate instruments with linear scales, and analyze data that shows a linear trend over time, such as temperature changes or position in uniform motion.

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Real-World Examples

An employee starts with a salary of $50,000 per year and is guaranteed an annual raise of $2,500. What will their salary be in their 10th year, and what are their total earnings over the first 10 years?
  1. This is an AP with first term a₁ = 50000, common difference d = 2500, and n = 10.
  2. Calculate the 10th year's salary using aₙ = a₁ + (n-1)d: a₁₀ = 50000 + (10-1) * 2500 = $72,500.
  3. Calculate the total earnings using Sₙ = n/2 * (a₁ + aₙ): S₁₀ = 10/2 * (50000 + 72500) = 5 * 122500 = $612,500.
The salary in the 10th year will be $72,500, and the total earnings over 10 years will be $612,500.
A theater has 20 seats in the first row, 22 in the second, 24 in the third, and so on for 30 rows. How many seats are in the 30th row, and what is the total seating capacity of the theater?
  1. This sequence is an AP with a₁ = 20, d = 2, and n = 30.
  2. Find the number of seats in the last row using aₙ = a₁ + (n-1)d: a₃₀ = 20 + (30-1) * 2 = 20 + 58 = 78 seats.
  3. Calculate the total capacity using Sₙ = n/2 * (a₁ + aₙ): S₃₀ = 30/2 * (20 + 78) = 15 * 98 = 1470 seats.
There are 78 seats in the 30th row, and the total capacity is 1,470 seats.
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Real-World Scenarios

+d aₙ = a₁+(n−1)d salary increment schedule
Salary Increment Schedule
Annual pay rises of a fixed amount d form an AP: year 1 salary a₁, year 2: a₁+d, year 3: a₁+2d… The sum formula Sₙ=n/2·(a₁+aₙ) lets HR departments calculate total payroll cost over an n-year period instantly.
total seats = Sₙ stadium row count
Stadium Seating Count
A stadium with rows of 20, 22, 24, … seats (AP with d=2) has total capacity Sₙ=n/2·(20+(20+2(n−1))). Architects use the sum formula to plan stadium capacity, price tiers, and emergency evacuation routes without counting every seat.
angles: 0°, 30°, 60°… AP with d=30°
Clock Angles (AP)
Clock hour marks are at angles 0°, 30°, 60°, 90°… — an AP with first term 0° and common difference 30°. The 12th mark is at a₁₂=0+(12−1)×30°=330°. Clockmakers and digital display designers use AP to position tick marks and compute sweep angles.

Auditorium Seating: Many theaters, stadiums, and lecture halls have rows of seats where each row has a constant number of additional seats compared to the one in front of it. This design ensures better visibility for people in subsequent rows.

Stacked Objects: Items like logs, pipes, or cans are often stacked in a trapezoidal pile. The number of items in each layer forms an arithmetic progression, allowing for easy calculation of the total number of items in the stack.

Depreciation: The value of an asset, like a car or machine, can decrease by a fixed amount each year. This method, known as straight-line depreciation, follows an arithmetic progression, making it simple to calculate the asset's book value over time.

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Types of Arithmetic Progressions

TypeCommon Difference (d)DescriptionExample
Increasingd > 0Each term is greater than the previous term.2, 5, 8, 11, ...
Decreasingd < 0Each term is less than the previous term.10, 8, 6, 4, ...
Constantd = 0All terms in the sequence are the same.7, 7, 7, 7, ...
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Common Mistakes

⚠️ Confusing the nth Term (aₙ) with the Sum (Sₙ): Students often calculate the value of the last term when the question asks for the sum of all terms, or vice-versa. Always double-check whether you need a specific term's value or the total sum.
⚠️ Incorrect Term Number `n`: A common error is using `n` instead of `(n-1)` in the formula aₙ = a₁ + (n-1)d. Remember the formula accounts for the number of 'steps' or 'gaps' from the first term, and there are `n-1` steps to reach the nth term.
⚠️ Sign Errors with Common Difference (d): For decreasing sequences, the common difference `d` is negative. Forgetting the negative sign will lead to incorrect calculations for both the nth term and the sum.
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Study Strategy

1 🧠 Grasp the Fundamentals
  • Read the 'Definition of an Arithmetic Progression' to understand what a 'first term' (a₁) and 'common difference' (d) represent.
  • Study the 'Properties of Arithmetic Progressions' to learn how sequences behave when a constant is added, subtracted, or multiplied.
  • Review the 'Visualizing an Arithmetic Progression' section to connect the abstract formula to a concrete number line or graph.
  • Differentiate between the 'Types of Arithmetic Progressions' (increasing, decreasing, constant) and how 'd' defines them.
2 📝 Commit Formulas to Memory
  • Write down the formula for the nth term, aₙ = a₁ + (n-1)d, repeatedly until you can recall it instantly.
  • Memorize the two primary formulas for the sum of n terms: Sₙ = n/2[2a₁ + (n-1)d] and Sₙ = n/2(a₁ + aₙ).
  • Use flashcards to quiz yourself on which sum formula is more efficient based on the known variables (e.g., last term is known).
  • Walk through the 'Proof of the Sum Formula' to understand its logic, which strengthens memory and comprehension.
3 ✍️ Practice with Guided Problems
  • Follow the 'Worked Example' step-by-step, then cover the solution and try to replicate the process on your own.
  • Before solving, practice identifying all given variables (a₁, n, d, aₙ) in a problem to determine the unknown.
  • Actively check your work against the 'Common Mistakes' section, especially for off-by-one errors in calculating 'n'.
  • Solve problems that require rearranging the formulas, such as finding 'd' or 'n' when other values are provided.
4 🌍 Connect to the Real World
  • Translate the 'Real-World Examples' (e.g., tiered seating, salary growth) into mathematical statements using AP notation.
  • Attempt to solve the problems presented in the 'Real-World Scenarios' section by applying the appropriate AP formulas.
  • Explore the 'Applications' section and explain how AP relates to concepts like simple interest calculations in finance.
  • Create your own real-world problem, like calculating the total distance a person runs over a month if they increase the distance daily by a fixed amount.
By systematically building from concepts to application, you can confidently master and apply the Arithmetic Progression formula in any context.

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