Maths Formulae Equations Quadratic Equation

Quadratic Equation – Formula & Roots

Master quadratic equation formulas, roots via the quadratic formula, and discriminant analysis. Essential for algebra le...
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Definition

A quadratic equation is a second-degree polynomial equation in a single variable x, with the general form ax² + bx + c = 0, where a, b, and c are constants and a cannot be zero. The solutions to this equation are called roots or zeros, and they represent the x-intercepts of the parabola described by the function y = ax² + bx + c.

\[ ax^2 + bx + c = 0 \]
General Form
Symbol/TermDescription
a, b, cCoefficients: constant real numbers that determine the parabola's shape and position. 'a' is the quadratic coefficient, 'b' is the linear coefficient, and 'c' is the constant term.
xVariable: the unknown value being solved for, representing the x-coordinates where the parabola intersects the x-axis.
Δ = b² - 4acDiscriminant: A value that determines the number and nature of the real solutions (roots) without having to solve the full equation.
r₁, r₂Roots or Solutions: The values of x that satisfy the equation, making the expression equal to zero.
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Key Formulas

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
The Quadratic Formula
\[ \Delta = b^2 - 4ac \]
The Discriminant

The discriminant determines the nature of the roots:

  • If Δ > 0, there are two distinct real roots.
  • If Δ = 0, there is exactly one repeated real root.
  • If Δ < 0, there are no real roots (two complex conjugate roots).
\[ r_1 + r_2 = -\frac{b}{a} \]
Vieta's Formula: Sum of Roots
\[ r_1 \cdot r_2 = \frac{c}{a} \]
Vieta's Formula: Product of Roots
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Diagram & Graph

x₁ x₂ vertex ax² + bx + c = 0 x = (−b ± √Δ) / 2a Δ = b² − 4ac Δ>0: two roots
Quadratic equation ax²+bx+c=0: the parabola's roots are where it crosses the x-axis. The discriminant Δ=b²−4ac determines the number of real roots.

A quadratic equation graphically represents a parabola. The roots of the equation, x₁ and x₂, are the points where the parabola intersects the x-axis. The coefficient a determines the parabola's direction: if a > 0, it opens upwards; if a < 0, it opens downwards. The coefficient c represents the y-intercept. The discriminant, Δ, indicates the number of x-intercepts: two for Δ > 0, one for Δ = 0, and none for Δ < 0.

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Properties

Second-Degree Polynomial: The highest power of the variable is 2, which results in a parabolic graph and at most two real solutions.

Number of Solutions: A quadratic equation can have zero, one, or two real solutions, which is determined by the value of its discriminant (b² - 4ac).

Symmetry: The graph of a quadratic function (a parabola) is symmetric about a vertical line passing through its vertex. The x-coordinate of the vertex is given by x = -b/2a.

Multiple Solution Methods: Quadratic equations can be solved by various methods, including factoring, completing the square, using the quadratic formula, and graphing.

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Proof of the Quadratic Formula

The quadratic formula can be derived by solving the general quadratic equation using the method of completing the square.

Step 1: Start with the standard form of the equation.

\[ ax^2 + bx + c = 0 \]

Step 2: Move the constant term c to the right side and divide the entire equation by a (since a ≠ 0).

\[ x^2 + \frac{b}{a}x = -\frac{c}{a} \]

Step 3: Complete the square on the left side by adding the square of half the coefficient of the x-term, which is (b/2a)², to both sides.

\[ x^2 + \frac{b}{a}x + \left(\frac{b}{2a}\right)^2 = -\frac{c}{a} + \left(\frac{b}{2a}\right)^2 \]

Step 4: Factor the left side as a perfect square and find a common denominator for the right side.

\[ \left(x + \frac{b}{2a}\right)^2 = \frac{b^2 - 4ac}{4a^2} \]

Step 5: Take the square root of both sides, remembering the plus-minus sign.

\[ x + \frac{b}{2a} = \pm\frac{\sqrt{b^2 - 4ac}}{2a} \]

Step 6: Isolate x to arrive at the quadratic formula.

\[ x = -\frac{b}{2a} \pm \frac{\sqrt{b^2 - 4ac}}{2a} = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
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Worked Example

Find the roots of the quadratic equation 2x² - 5x - 3 = 0.
  1. Identify the coefficients: a = 2, b = -5, c = -3.
  2. Calculate the discriminant: Δ = b² - 4ac = (-5)² - 4(2)(-3) = 25 + 24 = 49.
  3. Since Δ > 0, there are two distinct real roots.
  4. Substitute the coefficients into the quadratic formula: x = (-(-5) ± √49) / (2 * 2).
  5. Simplify the expression: x = (5 ± 7) / 4.
  6. Calculate the two roots: x₁ = (5 + 7) / 4 = 12 / 4 = 3 and x₂ = (5 - 7) / 4 = -2 / 4 = -0.5.
The roots are x = 3 and x = -0.5.
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Try It

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Applications

Physics & Engineering: Used to model projectile motion, calculate trajectories, and determine landing points. Also applied in designing parabolic structures like satellite dishes and suspension bridges, and in optimizing electrical circuits.

Business & Economics: Used to determine maximum profit and minimum cost. Quadratic equations help find break-even points where revenue equals cost, and to model supply and demand curves.

Geometry & Architecture: Used to solve problems involving area, such as finding the dimensions of a rectangle with a given area and perimeter. Architects use them to design curved structures and arches.

Finance & Investment: Used in models that calculate compound interest over short periods or to analyze investment growth that follows a quadratic pattern.

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Real-World Examples

A rocket is launched from the ground. Its height in meters after t seconds is given by the equation h(t) = -4.9t² + 196t. When will the rocket hit the ground again?
  1. We need to find the time 't' when the height 'h(t)' is 0. Set the equation to zero: -4.9t² + 196t = 0.
  2. This is a quadratic equation with a= -4.9, b = 196, c = 0.
  3. Factor out t: t(-4.9t + 196) = 0.
  4. This gives two solutions: t = 0 (the launch time) and -4.9t + 196 = 0.
  5. Solve for the second time: 196 = 4.9t, so t = 196 / 4.9 = 40.
The rocket will hit the ground again after 40 seconds.
A farmer wants to build a rectangular fence against a wall. She has 100 meters of fencing and wants the enclosed area to be 1200 square meters. What should the dimensions of the fence be?
  1. Let the side parallel to the wall be 'l' and the two sides perpendicular to the wall be 'w'. The total fencing is l + 2w = 100, so l = 100 - 2w.
  2. The area is A = l * w = (100 - 2w) * w = 1200.
  3. Expand and rearrange into standard quadratic form: 100w - 2w² = 1200 => 2w² - 100w + 1200 = 0.
  4. Divide by 2 to simplify: w² - 50w + 600 = 0.
  5. Solve using the quadratic formula (a=1, b=-50, c=600): w = (50 ± √((-50)² - 4*1*600)) / 2 = (50 ± √(2500 - 2400)) / 2 = (50 ± √100) / 2 = (50 ± 10) / 2.
  6. Two possible values for width w: w₁ = (50+10)/2 = 30 m, and w₂ = (50-10)/2 = 20 m.
  7. If w = 30 m, then l = 100 - 2(30) = 40 m. If w = 20 m, then l = 100 - 2(20) = 60 m.
The dimensions can be either 30m by 40m or 20m by 60m.
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Real-World Scenarios

max height h(t) = −½gt²+v₀t
Projectile Height and Landing Time
A ball thrown upward at 20 m/s follows h(t) = −5t² + 20t. Setting h = 0 gives 5t² − 20t = 0, so t(t − 4) = 0: the ball lands at t = 4 s. The maximum height is found at the vertex: t = 2 s, h = 20 m. Sports scientists use this quadratic equation to measure throw distances and optimise launch angles in javelin, shot put, and basketball.
l × w = 150 2l + 2w = 50 area = 150 m² l²−25l+150=0
Garden or Room Area Design
A rectangular garden has perimeter 50 m and area 150 m². With l + w = 25 and lw = 150, substituting gives l² − 25l + 150 = 0. Using the quadratic formula: l = (25 ± √(625−600))/2 = (25 ± 5)/2, so l = 15 m and w = 10 m. Architects and landscape designers solve this type of quadratic equation when fitting rooms or plots to a fixed boundary and area specification.
profit = −ax²+bx−c
Profit Maximisation in Economics
A company's profit function is P(x) = −2x² + 80x − 300 (dollars), where x is units sold. The maximum profit is at vertex x = −80/(2×−2) = 20 units, giving P = $500. Break-even points are found by setting P = 0: 2x² − 80x + 300 = 0, so x = 5 or x = 35. Economists and MBA students use this quadratic model to set optimal production levels.

Sports Trajectories: The path of a thrown baseball, a kicked soccer ball, or a basketball shot follows a parabolic arc. Quadratic equations can model this path to predict where the ball will land or if it will go through a hoop.

Bridge and Arch Design: Many famous bridges and arches, like the Gateway Arch in St. Louis, use parabolic shapes. This shape distributes weight and stress efficiently, and quadratic equations are fundamental to their structural design.

Satellite Dishes and Headlights: The parabolic reflectors in satellite dishes and car headlights are designed to focus waves (radio or light) to a single point. Quadratic equations define the precise curve needed for this focusing property to work.

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Types of Solutions

The type and number of solutions to a quadratic equation are determined entirely by the discriminant, Δ = b² - 4ac.

Discriminant (Δ)Type of RootsGraphical Interpretation
Δ > 0Two distinct real rootsThe parabola intersects the x-axis at two different points.
Δ = 0One repeated real root (a double root)The parabola's vertex touches the x-axis at exactly one point.
Δ < 0No real roots (two complex conjugate roots)The parabola is entirely above or entirely below the x-axis and never intersects it.
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Common Mistakes

⚠️ Sign Errors with '-b': A very common mistake is mishandling the '-b' term in the formula. If 'b' is negative (e.g., b = -5), then '-b' becomes positive (-(-5) = 5). Always double-check the signs.
⚠️ Incorrect Order of Operations: When calculating the discriminant (b² - 4ac), ensure you square 'b' first, then calculate the product 4ac, and finally perform the subtraction. Errors often occur when 'a' or 'c' are negative.
💡 Forgetting the Denominator: After calculating the numerator (-b ± √Δ), don't forget to divide the entire result by 2a. A frequent error is to only divide the square root part by 2a.
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Study Strategy

1 📚 Grasp the Core Concepts
  • Define a quadratic equation and identify its standard form: ax² + bx + c = 0.
  • Learn to correctly distinguish the coefficients a, b, and c in various examples.
  • Understand what the 'discriminant' (b² - 4ac) represents and how it determines the number of solutions.
  • Connect the formula's solutions (roots) to the x-intercepts on the equation's parabolic graph.
2 🧠 Commit the Formula to Memory
  • Write down the full quadratic formula, x = [-b ± sqrt(b² - 4ac)] / 2a, repeatedly until it's second nature.
  • Recite the formula out loud, associating each part with its purpose.
  • Use flashcards to practice substituting values for a, b, and c into the formula without fully solving.
  • Memorize the discriminant conditions: > 0 for two real solutions, = 0 for one, and < 0 for no real solutions.
3 ✍️ Solve and Verify
  • Follow a worked example step-by-step, focusing on the order of operations, especially with negative numbers.
  • Solve a variety of practice problems, including those with integer, fractional, and irrational solutions.
  • Always calculate the discriminant first to anticipate the type of solution you should find.
  • Verify your answers by plugging the calculated roots back into the original equation to see if they hold true.
4 🎯 Connect to Real-World Scenarios
  • Translate word problems about projectile motion (e.g., throwing a ball) into a standard quadratic equation.
  • Use the formula to solve for time, distance, or height in physics-based scenarios.
  • Tackle problems involving maximizing area or profit, which often result in a quadratic model.
  • Analyze solutions in context; for example, discard negative time values as non-physical answers.
Mastering this formula unlocks the power to model and solve countless real-world challenges.

Frequently Asked Questions

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