Maths Formulae Geometry Frustum of Right Circular Cone

Frustum of Cone – Volume and Surface Area Formulas

Learn the formulas for a frustum of a cone including volume, lateral surface area, and height. Advanced geometry referen...
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Definition of a Frustum

A frustum of a right circular cone is a three-dimensional shape formed by cutting a cone with two parallel planes perpendicular to its axis. This creates a solid with two circular bases of different radii connected by a curved lateral surface. It is essentially a cone with its top sliced off. The key components are the top radius (r₁), the bottom radius (r₂), the perpendicular height (h), and the slant height (s).

SymbolMeaning
r₁Radius of the smaller, top circular base
r₂Radius of the larger, bottom circular base
hPerpendicular distance (height) between the two bases
sSlant height, the distance along the slanted side surface
\[ s = \sqrt{h^2 + (r_2 - r_1)^2} \]
Slant Height
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Key Formulas

\[ V = \frac{1}{3}\pi h(r_1^2 + r_1r_2 + r_2^2) \]
Volume
\[ LSA = \pi(r_1 + r_2)s \]
Lateral Surface Area
\[ TSA = \pi r_1^2 + \pi r_2^2 + \pi(r_1 + r_2)s \]
Total Surface Area
\[ s = \sqrt{h^2 + (r_2 - r_1)^2} \]
Slant Height
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Diagram of a Frustum

r R h
Frustum of cone — top radius r, base radius R, height h

The diagram shows a truncated cone standing upright. The bottom circular base has a radius labeled r₂. The top circular base, which is parallel to the bottom base, has a smaller radius labeled r₁. The vertical, perpendicular distance between the centers of the two bases is the height, labeled h. The distance along the slanted edge of the shape, from the circumference of the top base to the circumference of thebottom base, is the slant height, labeled s.

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Properties of a Frustum

Rotational Symmetry: A right circular frustum has rotational symmetry around the axis connecting the centers of its two bases. Any rotation around this axis leaves the shape unchanged.

Parallel Bases: The two circular bases are parallel to each other and perpendicular to the central axis.

Proportional Scaling: The frustum is part of a larger, complete cone. The radii and heights of the frustum, the small removed cone, and the large original cone are all related through similar triangles.

Net (Development): The lateral surface of a frustum can be unrolled into a flat shape, which is a sector of an annulus (a ring).

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Proof of the Volume Formula

The volume of a frustum can be derived by considering it as a large cone with a smaller cone removed from its top. Let H be the height of the large cone and (H-h) be the height of the small removed cone.

\[ V_{frustum} = V_{large\,cone} - V_{small\,cone} \]

Using similar triangles, we can establish a relationship between the radii and heights: r₁(H-h) = r₂H. Solving for H gives the total height of the original cone: H = hr₂(r₂-r₁).

\[ V = \frac{1}{3}\pi r_2^2 H - \frac{1}{3}\pi r_1^2 (H - h) \]
Volume as a difference of two cones

By substituting the expression for H into this equation and simplifying, we arrive at the standard formula for the volume of a frustum.

\[ V = \frac{1}{3}\pi h(r_1^2 + r_1r_2 + r_2^2) \]
Simplified frustum volume formula
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Worked Example

A frustum has a top radius r₁ = 4 cm, a bottom radius r₂ = 7 cm, and a height h = 10 cm. Calculate its volume and total surface area.
  1. <strong>1. Calculate the slant height (s):</strong>
  2. s = √[h² + (r₂ - r₁)²]
  3. s = √[10² + (7 - 4)²] = √[100 + 3²] = √[100 + 9] = √109 ≈ 10.44 cm
  4. <strong>2. Calculate the Volume (V):</strong>
  5. V = (1/3)πh(r₁² + r₁r₂ + r₂²)
  6. V = (1/3)π(10)(4² + 4×7 + 7²) = (10π/3)(16 + 28 + 49) = (10π/3)(93) = 310π ≈ 973.89 cm³
  7. <strong>3. Calculate the Total Surface Area (TSA):</strong>
  8. TSA = πr₁² + πr₂² + π(r₁ + r₂)s
  9. TSA = π(4²) + π(7²) + π(4 + 7)(10.44)
  10. TSA = 16π + 49π + 11π(10.44) = 65π + 114.84π = 179.84π ≈ 565.0 cm²
The volume is approximately 973.89 cm³ and the total surface area is approximately 565.0 cm².
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Try It

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Applications

Architecture & Construction: Frustum shapes are used for structural elements like column capitals, tapered support piers, and foundation footings. They provide stability and distribute loads effectively.

Industrial & Manufacturing: Engineers design hoppers, funnels, and storage silos in the shape of frustums to control the flow and storage of granular materials or liquids.

Aerospace Engineering: The nozzles of rocket engines are often shaped like a series of frustums (a conical nozzle) to control the expansion and direction of exhaust gases, maximizing thrust.

Product Design: Many everyday objects, such as lampshades, buckets, and disposable cups, are frustums. This shape allows for stacking, provides stability, and is efficient for manufacturing.

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Real-World Examples

A plastic bucket is shaped like a frustum. Its top diameter is 30 cm, its bottom diameter is 20 cm, and its height is 25 cm. What is the volume of the bucket in liters? (1 liter = 1000 cm³)
  1. 1. Find the radii: r₁ = 30/2 = 15 cm, r₂ = 20/2 = 10 cm. Note: Conventionally r₂ > r₁, so let's set r₂=15 cm and r₁=10 cm.
  2. 2. Identify the height: h = 25 cm.
  3. 3. Use the volume formula: V = (1/3)πh(r₁² + r₁r₂ + r₂²)
  4. V = (1/3)π(25)(10² + 10×15 + 15²) = (25π/3)(100 + 150 + 225) = (25π/3)(475) ≈ 12435.3 cm³
  5. 4. Convert to liters: V = 12435.3 / 1000 ≈ 12.44 liters.
The volume of the bucket is approximately 12.44 liters.
A lampshade in the shape of a frustum has a top diameter of 20 cm, a bottom diameter of 40 cm, and a slant height of 30 cm. How much fabric is needed for the curved surface of the lampshade?
  1. 1. Find the radii: r₁ = 20/2 = 10 cm, r₂ = 40/2 = 20 cm.
  2. 2. Identify the slant height: s = 30 cm.
  3. 3. We need to find the Lateral Surface Area (LSA).
  4. 4. Use the LSA formula: LSA = π(r₁ + r₂)s
  5. LSA = π(10 + 20)(30) = π(30)(30) = 900π ≈ 2827.4 cm².
Approximately 2827.4 cm² of fabric is needed for the lampshade.
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Where Frustums Appear in the Real World

Buckets & Bowls
A typical bucket is a frustum — wider at the top than the bottom. Its volume V = ⅓πh(R²+Rr+r²) tells manufacturers exactly how many litres it holds.
Lampshades
Lampshades are frustums — the truncated cone shape directs light downward. Interior designers use the lateral surface area formula to calculate fabric requirements.
Drinking Cups
Paper and plastic cups are frustums. Fast food chains use the volume formula when designing cup sizes — a 500 ml cup has specific r₁, r₂, and h values calculated for that volume.

Drinking Cups and Buckets: Many containers for liquids are frustums. This shape makes them stable and allows them to be stacked easily for storage and transport.

Lampshades: The classic lampshade shape is a frustum. This design directs light downwards and outwards from the bulb in a controlled manner.

Architectural Columns: The capitals and bases of classical columns are often composed of frustums and other geometric shapes to create an aesthetically pleasing and structurally sound transition from the shaft to the ceiling or floor.

Traffic Cones: While technically a cone on top of a frustum base, the overall shape is iconic. The wide frustum base provides stability so the cone does not easily tip over.

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Types and Special Cases

The frustum formula is a general case that simplifies to other common shapes under specific limiting conditions.

Special CaseConditionResulting Shape & Formula
Equal Radiir₁ = r₂ = rA cylinder. The volume formula simplifies to V = πr²h.
Zero Top Radiusr₁ = 0A complete cone. The volume formula simplifies to V = (1/3)πr₂²h.
Zero Heighth → 0An annular disk (a flat ring). The volume approaches zero.
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Common Mistakes

⚠️ Confusing Height (h) and Slant Height (s): The vertical height 'h' is used for the volume calculation, while the slant height 's' is used for the lateral surface area. They are only equal if the radii are the same (a cylinder), which is not a frustum.
⚠️ Incorrectly Averaging Radii for Volume: A common error is to average the radii and use a cylinder-like formula. The volume is NOT πh((r₁+r₂)/2)². The correct formula V = (1/3)πh(r₁² + r₁r₂ + r₂²) must be used.
💡 Forgetting the Base Areas in TSA: When calculating the Total Surface Area (TSA), remember to add the area of BOTH the top circular base (πr₁²) and the bottom circular base (πr₂²) to the Lateral Surface Area (LSA).
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Study Strategy

1 📖 Build the Foundation
  • Define a frustum as the portion of a cone remaining after its top is cut off by a plane parallel to the base.
  • Identify the key variables from the diagram: larger radius (R), smaller radius (r), height (h), and slant height (l).
  • Understand the relationship between the variables by studying the Pythagorean link: l² = h² + (R-r)².
  • Review the 'Properties' section to grasp how the shape is formed from a larger cone minus a smaller cone.
2 🧠 Commit Formulas to Memory
  • Focus on the volume formula: V = (1/3)πh(R² + Rr + r²). Write it down 10 times.
  • Memorize the Lateral Surface Area (LSA) formula: LSA = π(R + r)l.
  • Learn the Total Surface Area (TSA) formula: TSA = π(R + r)l + πR² + πr².
  • Create flashcards with a diagram on one side and the three key formulas (Volume, LSA, TSA) on the other.
3 ✍️ Solve Guided Problems
  • Follow the 'Worked Example' step-by-step, recalculating each part to verify your understanding.
  • Cover the solution to the example and attempt to solve it independently before checking your work.
  • Find additional practice problems online, focusing on scenarios where you must first calculate the slant height (l).
  • Review the 'Common Mistakes' section to actively avoid errors like mixing up R and r or using the wrong area formula.
4 🌍 Connect to the Real World
  • Choose a real-world frustum like a bucket or lampshade, estimate its dimensions, and calculate its volume or surface area.
  • Solve application-based word problems, such as finding the capacity of a tapered plant pot.
  • Examine the 'Real-World Examples' list and visualize how you would measure R, r, and h for each object.
  • Try to formulate your own practical problem, like determining the amount of sheet metal needed to create a funnel.
Mastering the frustum formula is achievable by building a solid foundation, practicing consistently, and connecting the math to everyday objects.

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