Maths Formulae Integration Definite Integrals

Definite Integrals – Area and Bounded Regions

Understand definite integrals with upper and lower limits, and applications in calculating area under curves and physics...
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Definition of Definite Integrals

A definite integral, denoted as `∫_a^b f(x) dx`, represents the signed area of the region in the xy-plane that is bounded by the graph of a function `f(x)`, the x-axis, and the vertical lines `x=a` and `x=b`. The value `a` is the lower limit of integration and `b` is the upper limit. It is a fundamental concept in calculus that represents accumulation, such as total distance traveled from a velocity function or total work done by a variable force.

It is formally defined as the limit of a Riemann sum, which approximates the area with a series of rectangles. The Fundamental Theorem of Calculus provides a practical method for evaluating definite integrals by using an antiderivative of the function.

\[ \int_a^b f(x) \, dx = F(b) - F(a) \]
Fundamental Theorem of Calculus, Part 2
SymbolDescription
\[ \int_a^b \]Definite Integral - Integration from lower limit a to upper limit b
\[ f(x) \]Integrand - Function being integrated over the interval
\[ dx \]Differential Element - Infinitesimal width of rectangular approximations
\[ a, b \]Limits of Integration - Lower and upper bounds of the interval
\[ F(x) \]Antiderivative - Function whose derivative is f(x)
\[ \Delta x \]Subinterval Width - Width of each rectangle in Riemann sum
\[ x_i \]Sample Point - Point where function is evaluated in each subinterval
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Key Formulas for Definite Integrals

\[ \int_a^b f(x) \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} f(x_i) \Delta x = F(b) - F(a) \]
Core Definition and Evaluation
\[ \frac{d}{dx} \int_a^x f(t) \, dt = f(x) \]
Fundamental Theorem of Calculus, Part 1
\[ \text{Average value} = \bar{f} = \frac{1}{b-a} \int_a^b f(x) \, dx \]
Average Value of a Function
\[ \int_a^b u \, dv = [uv]_a^b - \int_a^b v \, du \]
Integration by Parts
\[ \int_a^b f(g(x)) g'(x) \, dx = \int_{g(a)}^{g(b)} f(u) \, du \]
Substitution Method
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Visualizing the Definite Integral

x y a b ∫ₐᵇ f(x) dx = Area under f(x) between a and b
Definite Integral ∫ₐᵇ f(x) dx: the exact area between the curve and the x-axis from x = a to x = b, computed as F(b) − F(a).

A diagram of a definite integral shows a function `y = f(x)` plotted on a Cartesian coordinate system. The area under the curve between two vertical lines at `x = a` and `x = b` is shaded. This shaded area represents the value of the integral. The region is bounded by the curve `y = f(x)` above, the x-axis below, and the lines `x = a` and `x = b` on the sides. The concept of the Riemann sum is often visualized by filling this area with many thin vertical rectangles, each with width `Δx` and height `f(x_i)`.

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Properties of Definite Integrals

\[ \int_a^a f(x) \, dx = 0 \]
Zero Interval
\[ \int_a^b f(x) \, dx = -\int_b^a f(x) \, dx \]
Reversing Limits
\[ \int_a^b c \cdot f(x) \, dx = c \int_a^b f(x) \, dx \]
Constant Multiple Rule
\[ \int_a^b [f(x) \pm g(x)] \, dx = \int_a^b f(x) \, dx \pm \int_a^b g(x) \, dx \]
Sum/Difference Rule
\[ \int_a^c f(x) \, dx = \int_a^b f(x) \, dx + \int_b^c f(x) \, dx \]
Additivity of Intervals

Comparison Property: If `f(x) ≤ g(x)` for all `x` in `[a, b]`, then `∫_a^b f(x) dx ≤ ∫_a^b g(x) dx`.

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Proof of the Fundamental Theorem of Calculus

We want to prove that if `F'(x) = f(x)`, then `∫_a^b f(x) dx = F(b) - F(a)`. We start by defining an area accumulation function, `A(x)`, which calculates the area under `f(t)` from `a` to `x`.

\[ A(x) = \int_a^x f(t) \, dt \]

By definition, the derivative of `A(x)` is the limit of the difference quotient. The term `A(x+h) - A(x)` represents the area of a thin strip under the curve from `x` to `x+h`.

\[ A'(x) = \lim_{h \to 0} \frac{A(x+h) - A(x)}{h} = \lim_{h \to 0} \frac{1}{h} \int_x^{x+h} f(t) \, dt \]

For a very small `h`, the area of this strip is approximately the area of a rectangle with width `h` and height `f(x)`. Thus, `∫_x^{x+h} f(t) dt ≈ h \cdot f(x)`. Substituting this into the limit gives us Part 1 of the Fundamental Theorem.

\[ A'(x) = \lim_{h \to 0} \frac{h \cdot f(x)}{h} = f(x) \]

This shows that `A(x)` is an antiderivative of `f(x)`. Since any two antiderivatives of `f(x)` can only differ by a constant, we can write `F(x) = A(x) + C`. Now we can evaluate `F(b) - F(a)`.

\[ F(b) - F(a) = (A(b) + C) - (A(a) + C) = A(b) - A(a) \]

From our definition of `A(x)`, we know that `A(b) = ∫_a^b f(t) dt` and `A(a) = ∫_a^a f(t) dt = 0`. Therefore, we arrive at the conclusion.

\[ \int_a^b f(x) \, dx = F(b) - F(a) \]

Worked Example: Integration by Parts

Calculate the definite integral `∫_0^π x sin(x) dx`.
  1. Identify `u` and `dv` for integration by parts, following the formula `∫ u dv = uv - ∫ v du`.
  2. Let `u = x` and `dv = sin(x) dx`. Then `du = dx` and `v = ∫sin(x) dx = -cos(x)`.
  3. Apply the integration by parts formula for definite integrals: `∫_a^b u dv = [uv]_a^b - ∫_a^b v du`.
  4. Substitute the parts into the formula: `∫_0^π x sin(x) dx = [-x cos(x)]_0^π - ∫_0^π (-cos(x)) dx`.
  5. Evaluate the first term: `[-π cos(π)] - [-0 cos(0)] = [-π(-1)] - 0 = π`.
  6. Evaluate the remaining integral: `∫_0^π cos(x) dx = [sin(x)]_0^π = sin(π) - sin(0) = 0 - 0 = 0`.
  7. Combine the results: `π - 0 = π`.
\[ \int_0^\pi x \sin(x) \, dx = \pi \]
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Applications of Definite Integrals

Engineering & Physics: Definite integrals are essential for calculating quantities that involve variable rates or distributions. This includes finding the work done by a variable force, calculating the center of mass of an object with non-uniform density, determining the force exerted by fluid pressure on a submerged surface, and finding moments of inertia.

Economics & Business: In economics, definite integrals are used to calculate consumer surplus and producer surplus, which represent the total benefit to consumers and producers in a market. They can also determine the total revenue generated over a period from a varying rate of income or the total cost from a marginal cost function.

Probability & Statistics: The probability of a continuous random variable falling within a certain range is found by integrating its probability density function (PDF) over that range. The total area under the PDF curve must equal 1, which is verified using a definite integral from -∞ to +∞.

Biology & Medicine: Definite integrals can model population growth over time by integrating a growth rate function. In pharmacology, they are used to determine the total exposure to a drug (Area Under the Curve, or AUC) in a patient's bloodstream over time, which is a key metric for drug efficacy and safety.

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Real-World Examples

A water tank is leaking at a rate of `r(t) = 200 - 4t` liters per hour, where `t` is the number of hours since the leak began. How much water is lost during the first 10 hours?
  1. The total water lost is the integral of the rate function from `t=0` to `t=10`.
  2. Set up the integral: `W = ∫_0^{10} (200 - 4t) dt`.
  3. Find the antiderivative of the integrand: `F(t) = 200t - 2t^2`.
  4. Apply the Fundamental Theorem of Calculus: `F(10) - F(0)`.
  5. Calculate `F(10) = 200(10) - 2(10)^2 = 2000 - 2(100) = 2000 - 200 = 1800`.
  6. Calculate `F(0) = 200(0) - 2(0)^2 = 0`.
  7. Subtract the values: `1800 - 0 = 1800`.
A total of 1800 liters of water is lost during the first 10 hours.
An object is pushed with a variable force `F(x) = 15x^2 + 10` Newtons over a distance from `x=0` to `x=2` meters. Calculate the total work done.
  1. Work done by a variable force is the integral of the force function over the distance: `W = ∫_a^b F(x) dx`.
  2. Set up the integral: `W = ∫_0^2 (15x^2 + 10) dx`.
  3. Find the antiderivative: `G(x) = (15x^3)/3 + 10x = 5x^3 + 10x`.
  4. Apply the Fundamental Theorem of Calculus: `G(2) - G(0)`.
  5. Calculate `G(2) = 5(2)^3 + 10(2) = 5(8) + 20 = 40 + 20 = 60`.
  6. Calculate `G(0) = 5(0)^3 + 10(0) = 0`.
  7. Subtract the values: `60 - 0 = 60`.
The total work done is 60 Joules.
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Real-World Scenarios

Velocity → Displacement Area = ∫v dt = displacement t₀ t₁ v
Physics — Kinematics
The displacement of an object equals ∫v(t) dt — the area under the velocity-time graph. GPS trackers and inertial navigation systems integrate accelerometer readings twice to find position.
Probability P(a ≤ X ≤ b) a b ∫ₐᵇ f(x)dx = P
Statistics — Probability
P(a ≤ X ≤ b) for a continuous distribution equals ∫ₐᵇ f(x) dx — the area under the PDF. Used by actuaries, risk analysts, and quality engineers to set tolerances and confidence intervals.
Work by Variable Force W = ∫F(x) dx x₀ x₁ F(x)
Engineering — Work & Energy
Work done by a variable force equals W = ∫F(x) dx — the area under the force-displacement graph. Used to calculate spring energy, rocket thrust work, and cable tension in lifting systems.

Architecture and Construction: An architect designing a building with a curved roof needs to calculate the amount of material required. They can model the curve of the roof with a function and use a definite integral to find the exact surface area, ensuring they order the correct amount of roofing material.

Environmental Science: To assess the total impact of a pollutant spill in a river, scientists measure the concentration rate of the pollutant flowing past a certain point over time. By integrating this rate function over the duration of the spill, they can calculate the total mass of pollutant that has passed, which is crucial for environmental impact assessment and cleanup planning.

Space Exploration: When launching a rocket, the thrust is not constant as fuel is consumed and the rocket's mass changes. Mission planners use definite integrals to calculate the total change in velocity (delta-v) by integrating the variable acceleration function over the duration of a rocket burn, which determines if the spacecraft can reach its target orbit.

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Types and Classifications

Definite integrals are classified based on the nature of their integration limits and the behavior of the integrand function within those limits.

TypeDescriptionExample
Proper IntegralThe interval of integration [a, b] is finite and the integrand f(x) is bounded and continuous on this interval.\[ \int_0^1 x^2 \, dx \]
Improper Integral (Type 1)The interval of integration is infinite, with one or both limits being ±∞.\[ \int_1^\infty \frac{1}{x^2} \, dx \]
Improper Integral (Type 2)The integrand f(x) has an infinite discontinuity (a vertical asymptote) at one or more points within the interval [a, b].\[ \int_0^1 \frac{1}{\sqrt{x}} \, dx \]
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Common Mistakes

⚠️ Forgetting to change the limits of integration during u-substitution. When you substitute `u = g(x)`, the original limits `x=a` and `x=b` must be converted to new limits `u=g(a)` and `u=g(b)`. Evaluating with the original limits is a frequent error.
⚠️ Confusing net area with total area. A standard definite integral `∫ f(x) dx` calculates net area, where regions below the x-axis are counted as negative. To find the total physical area, you must compute `∫ |f(x)| dx`, which may require splitting the integral where the function crosses the x-axis.
💡 When applying the Fundamental Theorem, remember the order is F(upper limit) - F(lower limit). A common slip is to calculate F(a) - F(b) instead of F(b) - F(a). Always subtract the evaluation at the bottom limit from the evaluation at the top limit.
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Study Strategy

1 🧠 Grasp the Core Concepts
  • Relate the definition of a definite integral to the concept of the 'area under a curve' using Riemann sums.
  • Clearly distinguish between a definite integral, which yields a numerical value, and an indefinite integral, which is a family of functions.
  • Study the 'Visualizing the Definite Integral' section to connect the notation ∫[a,b] f(x) dx to its geometric meaning.
  • Understand the specific roles of the integrand f(x), the lower and upper limits of integration (a, b), and the differential dx.
2 ✍️ Memorize the Essentials
  • Master the Fundamental Theorem of Calculus, Part 2: ∫[a,b] f(x) dx = F(b) - F(a), where F is the antiderivative of f.
  • Commit the key properties to memory, especially linearity, additivity of intervals, and reversing limits of integration.
  • Create flashcards for the standard integrals of common functions (power rule, trigonometric, exponential).
  • Review the 'Proof of the Fundamental Theorem of Calculus' to understand why the formula works, which aids retention.
3 🏋️ Practice with Guided Problems
  • Replicate the 'Worked Example: Integration by Parts' and then attempt a similar problem on your own.
  • Solve problems that require you to apply multiple properties, such as splitting an integral over a symmetric interval.
  • Practice finding the antiderivative F(x) first, then carefully evaluate F(b) - F(a) to avoid arithmetic errors.
  • Analyze the 'Common Mistakes' section and find practice problems that specifically test for those pitfalls, like mixing up the limits.
4 🌍 Apply to Real-World Scenarios
  • Use the 'Applications of Definite Integrals' guide to calculate the area between two distinct curves.
  • Calculate the total displacement of an object by integrating a velocity function over a specific time interval.
  • Work through a problem on finding the average value of a function, a key real-world application.
  • Model a scenario from the 'Real-World Examples' list, such as calculating total accumulated profit or resource consumption.
By systematically building your understanding from foundational theory to practical application, you can conquer definite integrals and unlock their problem-solving power.

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