Maths Formulae Algebra Geometric Progression

Geometric Progression Formulas – Series and Ratio

Learn geometric progression formulas including nth term, sum of n terms, and sum of infinite GP. Important for algebra a...
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Definition of a Geometric Progression

A geometric progression (or geometric sequence) is a sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. This sequence type is fundamental for understanding compound interest, population dynamics, radioactive decay, and technological scaling, modeling exponential growth and decay patterns through consistent multiplicative relationships between consecutive terms.

\[ a, ar, ar^2, ar^3, \ldots, ar^{n-1} \]
General form of a geometric sequence
\[ a_n = ar^{n-1} \]
Formula for the nth term

Where a is the first term of the sequence, and r is the common ratio (r ≠ 0).

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Key Formulas

\[ a_n = a r^{n-1} \]
The nth Term
\[ r = \frac{a_{k+1}}{a_k} \]
Common Ratio
\[ S_n = a \frac{1 - r^n}{1 - r} \]
Sum of the first n terms (for r ≠ 1)
\[ S_\infty = \frac{a}{1 - r} \]
Sum of an infinite geometric series (for |r| < 1)
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Visualizing a Geometric Progression

n aₙ a1 a2 a3 a4 a5 a6 aₙ = a₁ · rⁿ⁻¹ ratio r = aₙ₊₁/aₙ Sₙ = a₁(rⁿ−1)/(r−1) S∞ = a₁/(1−r) |r|<1 ×r
Geometric progression: each term multiplied by ratio r. Points follow an exponential curve. aₙ=a₁·rⁿ⁻¹; sum Sₙ=a₁(rⁿ−1)/(r−1); infinite sum S∞=a₁/(1−r) for |r|<1.

A geometric progression can be visualized on a 2D graph by plotting the term number (n) on the x-axis against the term's value (aₙ) on the y-axis. The resulting points (1, a), (2, ar), (3, ar²), etc., will lie on an exponential curve. If the common ratio `r` is greater than 1, the points will curve upwards, showing exponential growth. If `r` is between 0 and 1, the points will curve downwards towards the x-axis, showing exponential decay. If `r` is negative, the points will oscillate between positive and negative values, alternating above and below the x-axis.

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Properties of Geometric Progressions

The behavior of a geometric progression is entirely determined by its common ratio, r.

Common Ratio (r)Behavior of SequenceConvergence of Series
r > 1Terms increase exponentially (growth)Diverges
0 < r < 1Terms decrease exponentially (decay)Converges
r = 1All terms are constant (a, a, a, ...)Diverges (unless a=0)
r < 0Terms alternate in sign (oscillating)Converges if |r| < 1, Diverges if |r| ≥ 1

Geometric Mean: Any term in a geometric progression is the geometric mean of its two adjacent terms.

\[ a_n = \sqrt{a_{n-1} \cdot a_{n+1}} \]
Geometric Mean Property

Logarithmic Property: The logarithms of the terms of a geometric progression form an arithmetic progression.

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Proof of the Finite Sum Formula

We want to derive the formula for the sum of the first `n` terms of a geometric progression, denoted by Sₙ.

\[ S_n = a + ar + ar^2 + \ldots + ar^{n-1} \]
Step 1: Write out the sum

Next, multiply the entire equation by the common ratio `r`.

\[ rS_n = ar + ar^2 + ar^3 + \ldots + ar^{n} \]
Step 2: Multiply the sum by r

Now, subtract the second equation from the first. Notice that most of the terms on the right side cancel out.

\[ S_n - rS_n = (a + ar + \ldots + ar^{n-1}) - (ar + ar^2 + \ldots + ar^{n}) \]
Step 3: Subtract the two equations
\[ S_n - rS_n = a - ar^n \]
Step 4: Simplify after cancellation

Finally, factor out Sₙ on the left side and `a` on the right side, then solve for Sₙ, assuming r ≠ 1.

\[ S_n(1 - r) = a(1 - r^n) \]
Step 5: Factor both sides
\[ S_n = a \frac{1 - r^n}{1 - r} \]
Step 6: Isolate Sₙ to get the final formula
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Worked Example

Given a geometric sequence that starts with 2, 6, 18, ..., find the 8th term (a₈) and the sum of the first 8 terms (S₈).
  1. Identify the first term `a`. Here, a = 2.
  2. Calculate the common ratio `r` by dividing the second term by the first: r = 6 / 2 = 3.
  3. Use the formula for the nth term, `aₙ = arⁿ⁻¹`, to find a₈: `a₈ = 2 * 3⁸⁻¹ = 2 * 3⁷ = 2 * 2187 = 4374`.
  4. Use the formula for the sum of the first n terms, `Sₙ = a(1 - rⁿ) / (1 - r)`: `S₈ = 2(1 - 3⁸) / (1 - 3)`.
  5. Calculate the values: `S₈ = 2(1 - 6561) / (-2) = 2(-6560) / (-2) = -13120 / -2 = 6560`.
The 8th term is 4374 and the sum of the first 8 terms is 6560.
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Try It

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Applications of Geometric Progressions

Finance & Investment: Financial analysts use geometric progressions for calculating compound interest, investment returns, annuity values, and modeling exponential wealth accumulation in retirement planning and portfolio management.

Biology & Population Dynamics: Biologists apply geometric sequences for modeling population growth, bacterial reproduction, and viral spread, analyzing biological processes with constant growth rates over time periods.

Computer Science & Technology: Computer scientists use geometric progressions for analyzing recursive algorithms (like binary search), memory allocation patterns, network growth models, and computational complexity in exponential time problems.

Physics & Nuclear Science: Physicists apply geometric sequences for radioactive decay calculations, half-life analysis, and modeling chain reactions in nuclear physics.

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Real-World Examples

A person invests $5,000 in an account that pays 6% annual compound interest. What will be the value of the investment after 8 years?
  1. This is a geometric progression where the initial amount (first term) is a = $5,000.
  2. The value increases by 6% each year, so the common ratio is r = 1 + 0.06 = 1.06.
  3. We want to find the value after 8 years, which corresponds to the 9th term of the sequence (since the 1st term is at year 0). We use the formula aₙ = arⁿ⁻¹ with n=9.
  4. Calculate the value: V = 5000 * (1.06)⁹⁻¹ = 5000 * (1.06)⁸.
  5. V ≈ 5000 * 1.5938 ≈ $7969.24.
The investment will be worth approximately $7,969.24 after 8 years.
A bouncing ball is dropped from a height of 10 meters. On each bounce, it returns to 70% of its previous height. What is the total vertical distance the ball travels before it comes to rest?
  1. The total distance is the initial drop plus the sum of all the upward and downward bounces.
  2. Initial drop = 10 m.
  3. The sequence of upward bounces is an infinite geometric series: 10*0.7, 10*(0.7)², 10*(0.7)³, ... Here, a = 7 and r = 0.7.
  4. The sum of upward distances is S_up = a / (1 - r) = 7 / (1 - 0.7) = 7 / 0.3 = 23.33 m.
  5. The downward bounces are the same, so S_down = 23.33 m.
  6. Total distance = Initial drop + S_up + S_down = 10 + 23.33 + 23.33 = 56.66 m.
The total vertical distance traveled by the ball is approximately 56.67 meters.
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Real-World Scenarios

fractal branching GP r=2
Tree Branch Fractal Growth
A tree's branching follows a GP: 1 trunk → 2 branches → 4 → 8… At depth n there are 2ⁿ branches. Biologists use the GP formula aₙ=a₁·rⁿ⁻¹ to model lung bronchioles (r≈2.8 per level), blood vessel networks, and river tributary systems.
compound interest GP A = P(1+r)ⁿ
Compound Interest Growth
Annual balances A₁=P(1+r), A₂=P(1+r)², … form a GP with ratio (1+r). The sum S∞=a₁/(1−r) for |r|<1 gives the present value of a perpetuity — used by pension funds, bond pricing models, and mortgage amortisation tables.
bouncing ball GP r=0.7
Bouncing Ball Total Distance
A bouncing ball reaches heights h, rh, r²h, … (GP, r<1). Total distance = h·(1+r)/(1−r) using the infinite GP sum S∞=a/(1−r). Sports scientists use this to characterise ball "bounciness" (coefficient of restitution), and engineers apply it to vibration damping analysis.

Fractal Patterns in Nature
The branching of trees, the structure of a fern, or the shape of a coastline all exhibit self-similarity, a concept built upon geometric progressions. Each smaller branch or frond is a scaled-down version of the larger one, following a consistent multiplicative rule that creates these complex, natural fractals.

Musical Harmony
The frequencies of notes in the Western musical scale form a geometric progression. Each of the 12 semitones in an octave has a frequency that is the twelfth root of 2 (approximately 1.059) times the frequency of the one before it. This ensures that the ratio between any two notes is the same, regardless of the key.

Digital Image Zooming
When you zoom in or out of a digital photo, the software scales the image by a certain factor. Performing this action repeatedly is a geometric progression. Zooming in by 20% multiple times applies a common ratio of 1.2 to the image size with each step.

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Types and Classifications

Geometric progressions are classified based on the value of their common ratio, r, which determines the sequence's behavior and whether its corresponding series has a finite sum.

TypeCondition on Ratio (r)Description
Convergent Sequence|r| < 1Terms approach zero. The infinite series has a finite sum.
Divergent Sequence|r| > 1Terms grow exponentially towards ±infinity. The series does not have a finite sum.
Constant Sequencer = 1All terms are the same as the first term, `a`.
Oscillating Sequencer < 0Terms alternate between positive and negative values.
Boundary Divergentr = -1Terms oscillate between `a` and `-a`. The series diverges.
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Common Mistakes

⚠️ Using the infinite sum formula when |r| ≥ 1. The formula S∞ = a / (1 - r) is only valid for convergent series where the absolute value of the common ratio is less than 1. Applying it to a divergent series gives an incorrect and meaningless result.
⚠️ Confusing the exponent in term vs. sum formulas. The nth term formula is aₙ = arⁿ⁻¹ (exponent is n-1), while the finite sum formula is Sₙ = a(1 - rⁿ) / (1 - r) (exponent is n). Using the wrong exponent is a frequent error.
⚠️ Incorrectly calculating the common ratio. The ratio `r` is found by dividing any term by its *preceding* term (e.g., a₃ / a₂). Reversing the division (e.g., a₂ / a₃) will give the reciprocal (1/r) and lead to wrong answers.
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Study Strategy

1 📖 Solidify the Foundation
  • Clearly define 'common ratio' (r) and practice finding it by dividing any term by its preceding term.
  • Articulate the difference between a finite and an infinite geometric progression using examples.
  • Explain the critical condition for the convergence of an infinite GP, which is that the absolute value of r must be less than 1 (|r| < 1).
  • Review the 'Properties' section to understand how multiplying or dividing the entire sequence by a constant affects the GP.
2 🧠 Commit Formulas to Memory
  • Write out the formula for the nth term, a_n = a * r^(n-1), ten times, focusing on the meaning of each variable.
  • Use flashcards to memorize the formula for the sum of the first n terms, S_n = a(1-r^n) / (1-r), noting the condition r ≠ 1.
  • Practice deriving the sum to infinity formula, S_∞ = a / (1-r), by considering what happens to r^n in the finite sum formula as n approaches infinity when |r| < 1.
  • Verbally explain each formula to a friend or study partner to reinforce your understanding and recall.
3 ✍️ Practice with Purpose
  • Re-solve the 'Worked Example' from the formula page without looking at the solution, then compare your steps.
  • Complete practice problems where you must find a missing element: the first term (a), the common ratio (r), the number of terms (n), or a specific term (a_n).
  • Tackle problems involving the sum of a finite series, ensuring you can rearrange the formula to solve for different variables.
  • Intentionally attempt problems highlighted in the 'Common Mistakes' section to build resilience against typical errors, like off-by-one mistakes in 'n'.
4 🌍 Connect to the Real World
  • Model a compound interest investment scenario, treating the principal as 'a' and (1 + interest rate) as 'r'.
  • Calculate the total depreciation of a car over several years, identifying the initial value and the constant rate of depreciation.
  • Analyze a 'Real-World Scenario' like radioactive decay, setting up the GP formula to find the amount of substance remaining after a certain number of half-lives.
  • Create and solve your own word problem based on a scenario like population growth or the spread of information on social media.
By systematically building from concepts to application, you will master geometric progressions and learn to model the patterns of exponential change in the world.

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