Physics Formulae Periodic Motion Change Of Period Following The Change Of The Height

Subset – Definition and Properties

Calculate how a pendulum's swing time changes with altitude. Our guide explains the period change with height formula, i...
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Change Of Period Following The Change Of The Height

The period of a pendulum, the time it takes to complete one full swing, is dependent on the local gravitational acceleration (g). According to Newton's law of universal gravitation, the force of gravity, and thus the acceleration g, decreases as the distance from the center of the Earth increases. Consequently, when a pendulum is moved to a higher altitude, it experiences a weaker gravitational pull. This reduction in gravity causes the pendulum to swing more slowly, resulting in an increase in its period. For altitudes that are small compared to the Earth's radius, this change is approximately linear, meaning the fractional increase in the pendulum's period is directly proportional to the height it has been raised.

This phenomenon was first observed experimentally in the 17th century and provided early evidence for the variation of gravity across the Earth's surface. While often a small effect, it is critical for precision timekeeping, geodesy (the study of Earth's shape and gravitational field), and high-altitude scientific measurements.

Physical Properties

The change in a pendulum's period with height is a direct consequence of the variation of gravitational acceleration with altitude. As a pendulum's elevation increases, the local gravitational force weakens, causing its period to lengthen, meaning it swings more slowly.

PropertyDetails
NatureThe change in period is a scalar quantity, as it represents a change in a time interval.
SI UnitsThe period (T) and the change in period (ΔT) are both measured in seconds (s).
MagnitudeThe magnitude is typically very small for terrestrial changes in height and is proportional to the initial period and the fractional change in altitude (h/R).
Dimensional Formula[T]. Both the period and its change have the dimension of time.
Governing PrinciplesThis effect is governed by the formula for a simple pendulum's period and Newton's Law of Universal Gravitation, which dictates how gravitational acceleration 'g' changes with distance from a planet's center.
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Diagram & Visualization

Earth Surface T g T' g' h At altitude h, g' < g, so T' > T
A pendulum's period (T) increases at higher altitudes (h) because gravitational acceleration (g) decreases.
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Key Formulas

\[ \frac{\Delta T}{T} = \frac{h}{R} \]
Fractional Change in Period with Height (Approximation)
\[ T = 2\pi\sqrt{\frac{l}{g}} \]
Period of a Simple Pendulum
\[ g_h = \frac{GM}{(R + h)^2} \]
Gravitational Acceleration at Height h
\[ \text{Daily error (seconds)} = \frac{h}{R} \times 86400 \]
Daily Timekeeping Error
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Variables

SymbolQuantitySI UnitDescription
\( \Delta T / T \)Fractional Change in PeriodDimensionlessThe proportional change in the pendulum's period.
\( h \)Heightmeter (m)The altitude above the Earth's surface.
\( R \)Earth's Radiusmeter (m)The mean radius of the Earth, approximately 6.371 × 10⁶ m.
\( T_0 \)Initial Periodsecond (s)The period of the pendulum at the reference height (e.g., sea level).
\( T_h \)Final Periodsecond (s)The period of the pendulum at height h.
\( g_0 \)Initial Gravitational Accelerationm/s²The gravitational acceleration at the reference height.
\( g_h \)Final Gravitational Accelerationm/s²The gravitational acceleration at height h.
\( l \)Pendulum Lengthmeter (m)The length of the pendulum from the pivot to the center of mass.
\( G \)Gravitational ConstantN·m²/kg²The universal gravitational constant.
\( M \)Mass of the Earthkilogram (kg)The total mass of the Earth.
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Derivation

The relationship is derived from Newton's law of universal gravitation and the formula for the period of a pendulum.

1. Gravitational Acceleration at Different Altitudes

Gravitational acceleration at the Earth's surface (radius R) is:

\[ g_0 = \frac{GM}{R^2} \]

At a height h above the surface, the distance from the center is (R + h), so the acceleration is:

\[ g_h = \frac{GM}{(R + h)^2} \]

2. Ratio of Gravitational Accelerations

The ratio of the acceleration at height h to the acceleration at the surface is:

\[ \frac{g_h}{g_0} = \frac{GM/(R + h)^2}{GM/R^2} = \frac{R^2}{(R + h)^2} = \frac{1}{(1 + h/R)^2} \]

3. Relating Period to Gravity

The period of a pendulum at the surface is \( T_0 = 2\pi\sqrt{l/g_0} \), and at height h is \( T_h = 2\pi\sqrt{l/g_h} \). The ratio of the periods is:

\[ \frac{T_h}{T_0} = \frac{2\pi\sqrt{l/g_h}}{2\pi\sqrt{l/g_0}} = \sqrt{\frac{g_0}{g_h}} \]

4. Combining Ratios and Approximating

Substituting the gravity ratio into the period ratio:

\[ \frac{T_h}{T_0} = \sqrt{\frac{1}{g_h/g_0}} = \sqrt{(1 + h/R)^2} = 1 + \frac{h}{R} \]

Note: An alternative derivation uses the binomial approximation. From \( \frac{g_h}{g_0} = (1 + h/R)^{-2} \), for \( h \ll R \), we can approximate \( (1 + h/R)^{-2} \approx 1 - 2h/R \). Then the period ratio becomes:

\[ \frac{T_h}{T_0} = \sqrt{\frac{g_0}{g_h}} \approx \sqrt{\frac{1}{1 - 2h/R}} = (1 - 2h/R)^{-1/2} \approx 1 + \frac{1}{2}\left(\frac{2h}{R}\right) = 1 + \frac{h}{R} \]

5. Finding the Fractional Change

The fractional change in period is defined as \( \Delta T / T_0 = (T_h - T_0) / T_0 \):

\[ \frac{\Delta T}{T_0} = \frac{T_h}{T_0} - 1 \approx \left(1 + \frac{h}{R}\right) - 1 = \frac{h}{R} \]
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Types & Special Cases

The calculation for the change in a pendulum's period varies based on the magnitude of the altitude change relative to the radius of the Earth.

Type / CaseDescriptionWhen to Use
Small Height Change (h << R)For small changes in height (h) compared to the Earth's radius (R), a linear approximation is used. The fractional change in period is approximately equal to the fractional change in height: ΔT/T ≈ h/R.This is used for nearly all terrestrial applications, like calculating the time difference for a pendulum clock moved from sea level to a mountain.
Large Height Change (h is significant)When the height change is a significant fraction of the Earth's radius, the exact formula for gravitational acceleration at height h must be used without approximation. The relationship is non-linear.This is necessary for calculations involving satellites, high-altitude research, or theoretical problems where precision over large distances is required.
Change in Depth (below surface)If a pendulum is taken below the Earth's surface into a mine, the gravitational acceleration decreases. Assuming uniform density, g decreases linearly with distance to the center, leading to a different formula for the change in period.This case is relevant for geophysical studies, gravimetry, and analyzing pendulum behavior deep within the Earth.
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Worked Example

<p>A pendulum is moved from sea level to an altitude of h = 3000 m. Given the Earth's radius R ≈ 6.371 × 10⁶ m, calculate the fractional change in its period and the corresponding time lost per day.</p>
  1. <b>1. Calculate the fractional change in period (ΔT/T):</b><br>Use the formula \( \frac{\Delta T}{T} = \frac{h}{R} \).<br>Substitute the given values:<br>\[ \frac{\Delta T}{T} = \frac{3000 \text{ m}}{6.371 \times 10^6 \text{ m}} \]<br>\[ \frac{\Delta T}{T} \approx 4.708 \times 10^{-4} \]
  2. <b>2. Calculate the daily time error:</b><br>The total number of seconds in a day is 24 × 60 × 60 = 86,400 s.<br>Multiply the fractional change by the total seconds in a day.<br>\[ \text{Daily error} = \left( \frac{\Delta T}{T} \right) \times 86400 \text{ s} \]<br>\[ \text{Daily error} = (4.708 \times 10^{-4}) \times 86400 \text{ s} \approx 40.7 \text{ s} \]
<p>The fractional change in the period is approximately 4.71 × 10⁻⁴ (or 0.0471%). The clock will run slow, losing about 40.7 seconds per day.</p>
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Try It

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Applications

Geodesy and Geophysics: Pendulums, or more modern gravimeters that operate on similar principles, are used to measure local variations in Earth's gravitational field. After correcting for altitude, remaining anomalies can indicate variations in subsurface density, helping to locate mineral deposits, magma chambers, or underground water reserves.

Precision Timekeeping: For high-precision pendulum clocks, moving the clock between locations at different altitudes (e.g., from a sea-level laboratory to a mountain observatory) requires recalibration to account for the change in g. The formula allows for a precise prediction of the necessary adjustment.

Aviation and Aerospace: While modern aircraft use quartz and atomic clocks, understanding the effect of gravity variation is fundamental in physics and astronautics. For example, the gravitational time dilation predicted by General Relativity, which affects GPS satellites, is a related concept where gravitational potential, not just altitude, affects the flow of time.

Historical Surveying: Before modern technology, expeditions used pendulum measurements to help determine the precise shape of the Earth (its oblateness) and to establish accurate geographical coordinates in challenging terrains like mountain ranges.

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Real-World Examples

<p>A precision pendulum clock, accurate at sea level (T₀ = 2.000 s), is moved to a mountain observatory at an altitude of h = 2,400 m. Calculate the new period and the daily timekeeping error. (Use R = 6.371 × 10⁶ m).</p>
  1. <b>1. Calculate the fractional period change:</b><br>Using the formula \( \frac{\Delta T}{T} = \frac{h}{R} \):<br>\[ \frac{\Delta T}{T} = \frac{2,400}{6.371 \times 10^6} = 3.77 \times 10^{-4} \]
  2. <b>2. Calculate the new period at altitude:</b><br>The new period is \( T_h = T_0 (1 + \frac{\Delta T}{T}) \):<br>\[ T_h = 2.000 \text{ s} \times (1 + 3.77 \times 10^{-4}) = 2.000754 \text{ s} \]
  3. <b>3. Calculate the daily timekeeping error:</b><br>The error is the fractional change multiplied by the number of seconds in a day (86,400 s):<br>\[ \text{Daily error} = (3.77 \times 10^{-4}) \times 86400 \text{ s} = 32.6 \text{ seconds} \]
<p>The new period is 2.000754 s. The clock runs slow by 32.6 seconds per day at the observatory.</p>
<p>A portable chronometer based on a pendulum is taken on a flight at a cruising altitude of 11,000 m for 6 hours. Calculate the total time error accumulated during the flight due to altitude.</p>
  1. <b>1. Calculate the fractional period change at cruising altitude:</b><br>\[ \frac{\Delta T}{T} = \frac{h}{R} = \frac{11,000}{6.371 \times 10^6} = 1.73 \times 10^{-3} \]
  2. <b>2. Calculate the duration of the flight in seconds:</b><br>\[ t_{flight} = 6 \text{ hours} \times 3600 \text{ s/hour} = 21,600 \text{ s} \]
  3. <b>3. Calculate the total time error:</b><br>The error is the fractional change multiplied by the flight duration:<br>\[ \text{Error} = \left( \frac{\Delta T}{T} \right) \times t_{flight} = (1.73 \times 10^{-3}) \times 21,600 \text{ s} \approx 37.4 \text{ seconds} \]
<p>The chronometer will run slow, accumulating an error of approximately 37.4 seconds during the 6-hour flight.</p>
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Real-World Scenarios

High-Altitude Clock
A pendulum clock accurate at sea level will run slower at a higher altitude because weaker gravity increases the pendulum's period.
Gravity on Everest
As mountaineers ascend a peak like Everest, a pendulum's period increases due to the diminishing gravitational force at higher altitudes.
Deep Mine Timing
Counter-intuitively, gravity weakens deep inside the Earth, causing a pendulum in a mine to have a longer period than at the surface.

High-Altitude Cities

A master clockmaker in Amsterdam (at sea level) builds a highly precise grandfather clock. When the clock is sold and moved to Denver, Colorado (altitude ~1600 m), the new owner finds it consistently loses about 22 seconds per day. This is not a defect in the clock but a direct, predictable consequence of the weaker gravity at Denver's higher altitude.

Mountain Climbing Expeditions

A scientific team on an expedition to Mount Everest uses a portable pendulum-based device to measure local gravity. As they ascend from Base Camp (~5,300 m) to higher camps, they observe a steady increase in the pendulum's period. This data must be carefully correlated with their precise altitude to map the mountain's gravitational profile.

Underground Mines

Conversely, a timing instrument used in a deep mine shaft, such as the Mponeng gold mine in South Africa (up to 4 km deep), would be closer to the Earth's center. However, the effect is complicated because the mass of the rock shell above the instrument no longer pulls it 'down'. The net effect is that gravity also decreases as one descends into the Earth, causing a pendulum to slow down, similar to the effect of increasing altitude.

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Limitations

⚠️ The formula \( \Delta T / T = h/R \) is a linear approximation based on the binomial expansion, valid only when the height \( h \) is much smaller than the Earth's radius \( R \) (i.e., \( h \ll R \)). This holds true for all terrestrial applications, including mountains and aircraft, but would be inaccurate for orbital altitudes.
💡 The model assumes a perfectly spherical, non-rotating Earth with uniform density. In reality, Earth is an oblate spheroid (wider at the equator) and its rotation causes a centrifugal effect that reduces effective gravity, most significantly at the equator. Local geology (e.g., dense mountain ranges or ore deposits) also causes small variations in \(g\).
💡 This formula only accounts for the change in period due to altitude. In practice, other environmental factors, especially temperature (which causes thermal expansion/contraction of the pendulum rod), can have a comparable or even greater effect on the period and must also be considered for precision instruments.

Common Mistakes

⚠️ Incorrect Sign: A frequent mistake is being unsure if the period increases or decreases. Remember: Higher altitude → Weaker gravity → Slower swing → Longer period. The change \( \Delta T \) is always positive, and clocks always run slower.
⚠️ Unit Mismatch: The formula \( h/R \) is a ratio and requires \( h \) and \( R \) to be in the same units. A common error is using \( h \) in kilometers and \( R \) in meters, or vice versa, leading to an error of a factor of 1000. Always convert both to meters before calculating.
⚠️ Confusing with Other Effects: Students sometimes incorrectly assume the pendulum's mass or the amplitude of its swing affects the period change due to altitude. The fractional change \( \Delta T/T \) is independent of the pendulum's specific characteristics (length, mass) and depends only on the change in altitude.
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Units and Dimensions

Dimensional analysis confirms the consistency of the formula. The left side, \( \Delta T / T \), is a ratio of time to time, making it dimensionless.

\[ \frac{[\Delta T]}{[T]} = \frac{\text{[T]}}{\text{[T]}} = 1 \]

The right side, \( h / R \), is a ratio of height (a length) to radius (a length), which is also dimensionless.

\[ \frac{[h]}{[R]} = \frac{\text{[L]}}{\text{[L]}} = 1 \]

Since both sides are dimensionless, the formula is dimensionally consistent.

QuantitySymbolSI UnitDimensional Formula
Period\( T \)second (s)\( [T] \)
Height\( h \)meter (m)\( [L] \)
Radius\( R \)meter (m)\( [L] \)
Gravitational Acceleration\( g \)meters per second squared (m/s²)\( [L][T]^{-2} \)
Length\( l \)meter (m)\( [L] \)
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Study Strategy

1 🧠 Grasp the Fundamentals
  • Start with the 'DEFINITION' section to understand why a pendulum's period is linked to gravitational acceleration (g).
  • Review the core concept: higher altitude leads to weaker gravity (smaller g), which causes a slower swing.
  • Internalize the logical flow: Higher Altitude → Weaker Gravity → Longer Period. This is the foundation of the formula.
  • Follow the 'Derivation' to see how the approximation for the change in g leads to the final formula for the change in period, ΔT.
2 📝 Commit the Formula to Memory
  • Write down the formula for the fractional change in period: ΔT/T ≈ h/R. Understand it as a simple ratio.
  • Identify the key variables: ΔT (change in period), T (original period), h (change in height), and R (radius of the Earth).
  • Use flashcards to link the formula ΔT ≈ T * (h/R) to its physical meaning: the change in period is proportional to the fractional change in height.
  • Practice rearranging the formula to solve for any variable, such as finding the height 'h' given a known change in period.
3 ✍️ Practice with Problems
  • Work through the 'Worked Example' step-by-step, focusing on how the values are substituted and the final answer is interpreted.
  • Review the 'COMMON_MISTAKES' section. Always remember that ΔT is positive because clocks run slower at higher altitudes ('Incorrect Sign' mistake).
  • Heed the 'Unit Mismatch' warning. Before calculating, ensure both height 'h' and Earth's radius 'R' are in the same units (e.g., both in meters).
  • Create a variation of the 'Worked Example' by changing the initial height or location to solidify your problem-solving skills.
4 🌍 Connect to Real-World Physics
  • Read the 'APPLICATIONS' section to see how this principle aids in Geodesy, helping geophysicists discover mineral deposits.
  • Consider the 'Precision Timekeeping' application. Why is this effect crucial for satellites but negligible for a clock moved between floors of a building?
  • Explore the 'Real-World Examples', such as the time dilation effect on GPS satellites, which require relativistic corrections for accuracy.
  • Think about how this formula would apply on other planets. Would a clock run slower or faster at the top of Olympus Mons on Mars?
Master the effect of altitude on time by understanding the core physics, practicing diligently, and connecting the formula to the world around you.

Frequently Asked Questions

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