Physics Formulae Mechanics Archimedes' Principle

Subset – Definition and Properties

Learn how the Archimedes' Principle formula calculates the upward buoyant force on an object in a fluid. Perfect for stu...
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Definition of Archimedes' Principle

Archimedes' Principle states that any object wholly or partially submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the object. This fundamental principle explains why objects float or sink and is the basis for understanding buoyancy in liquids and gases. The principle applies to all fluids—liquids and gases—and is independent of the shape, size, or composition of the submerged object, depending only on the volume of fluid displaced.

Historical Context: The principle was discovered by Archimedes of Syracuse (287-212 BCE) while solving a problem for King Hiero II. According to legend, Archimedes realized the principle while taking a bath and observing the water displacement, famously shouting "Eureka!" ("I have found it!"). He used this discovery to determine if a royal crown was made of pure gold without damaging it, marking one of the first applications of non-destructive material testing.

Physical Properties

Archimedes' Principle defines the properties of the buoyant force, a fundamental vector quantity in fluid mechanics that governs the behavior of objects in fluids.

PropertyDetails
NatureThe buoyant force is a vector quantity.
SI UnitsNewtons (N), as it is a type of force.
MagnitudeEqual to the weight of the fluid displaced by the object. It is calculated as the product of the fluid's density (ρ), the submerged volume of the object (V), and the acceleration due to gravity (g).
DirectionThe buoyant force always acts vertically upward, opposing the force of gravity.
Point of ApplicationThe force acts through the center of buoyancy, which is the geometric center (centroid) of the displaced volume of fluid.
Dimensional Formula[M][L][T]⁻², the standard dimensions for force.
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Diagram & Visualization

Fb Wfluid Fb = Wfluid
Archimedes' Principle: The upward buoyant force (F_b) on a submerged object equals the weight of the fluid it displaces (W_fluid).
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Key Formulas

\[ F_b = \rho_{fluid} V_{displaced} g \]
Archimedes' Principle - Buoyant Force
\[ \frac{V_{submerged}}{V_{total}} = \frac{\rho_{object}}{\rho_{fluid}} \]
Flotation Condition for Partially Submerged Objects

The condition for an object's behavior in a fluid is determined by comparing its density to the fluid's density:

  • Object Floats: \( \rho_{object} < \rho_{fluid} \) (Buoyant force > Weight initially)
  • Neutral Buoyancy: \( \rho_{object} = \rho_{fluid} \) (Buoyant force = Weight)
  • Object Sinks: \( \rho_{object} > \rho_{fluid} \) (Buoyant force < Weight)
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Variables and Symbols

SymbolQuantitySI UnitDescription
\( F_b \)Buoyant ForceNewton (N)The upward force exerted by the fluid on the submerged or floating object.
\( \rho_{fluid} \)Fluid Densitykg/m³The mass per unit volume of the fluid in which the object is submerged.
\( V_{displaced} \)Displaced VolumeThe volume of the fluid that is moved out of the way by the object. For a fully submerged object, this equals the object's total volume.
\( g \)Gravitational Accelerationm/s²The acceleration due to gravity, approximately 9.8 m/s² on Earth's surface.
\( \rho_{object} \)Object Densitykg/m³The average mass per unit volume of the object.
\( V_{total} \)Total Volume of ObjectThe entire volume occupied by the object.
\( V_{submerged} \)Submerged VolumeThe portion of the object's volume that is below the fluid's surface.
\( W \)WeightNewton (N)The gravitational force on an object, calculated as \( W = mg \).
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Derivation from First Principles

Archimedes' Principle can be derived by considering the pressure difference a fluid exerts on a submerged object. Let's consider a rectangular object of height \( h \) and face area \( A \) fully submerged in a fluid of density \( \rho_{fluid} \).

1. The pressure on the top surface of the object, at a depth \( d_{top} \), is given by the hydrostatic pressure formula:

\[ P_{top} = \rho_{fluid} g d_{top} \]

2. This pressure results in a downward force on the top surface:

\[ F_{down} = P_{top} A = \rho_{fluid} g d_{top} A \]

3. Similarly, the pressure on the bottom surface, at depth \( d_{bottom} = d_{top} + h \), is greater:

\[ P_{bottom} = \rho_{fluid} g d_{bottom} = \rho_{fluid} g (d_{top} + h) \]

4. This results in an upward force on the bottom surface:

\[ F_{up} = P_{bottom} A = \rho_{fluid} g (d_{top} + h) A \]

5. The net force due to the fluid is the buoyant force \( F_b \), which is the difference between the upward and downward forces. The horizontal forces cancel out due to symmetry.

\[ F_b = F_{up} - F_{down} = \rho_{fluid} g (d_{top} + h) A - \rho_{fluid} g d_{top} A \]

6. Simplifying the expression:

\[ F_b = \rho_{fluid} g h A \]

7. Since the volume of the rectangular object is \( V = h \times A \), which is also the volume of the displaced fluid \( V_{displaced} \), we arrive at Archimedes' Principle:

\[ F_b = \rho_{fluid} g V_{displaced} \]
The buoyant force is equal to the weight of the fluid displaced by the object.
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Types & Special Cases

The principle's application results in three primary conditions for an object in a fluid, based on the relationship between the object's density and the fluid's density.

Type / CaseDescriptionWhen to Use
Floating ObjectAn object floats when the buoyant force equals its weight, with only a part of its volume submerged. The net force on the object is zero.Used when the object's average density is less than the fluid's density (ρ_obj < ρ_fluid).
Sinking ObjectAn object sinks when its weight is greater than the maximum possible buoyant force (when fully submerged). There is a net downward force.Used when the object's average density is greater than the fluid's density (ρ_obj > ρ_fluid).
Neutrally Buoyant (Suspended)An object remains suspended at a constant depth when its weight is exactly equal to the buoyant force when fully submerged. The net force is zero.Used when the object's average density is equal to the fluid's density (ρ_obj = ρ_fluid).
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Worked Example (Numerical)

An object with a volume of 0.02 m³ is fully submerged in a fluid with a density of 1100 kg/m³. Given that the acceleration due to gravity is \( g = 9.8 \) m/s², calculate the buoyant force acting on the object.
  1. Identify the given values: \( V_{displaced} = 0.02 \) m³ (since it's fully submerged), \( \rho_{fluid} = 1100 \) kg/m³, and \( g = 9.8 \) m/s².
  2. Use the formula for buoyant force: \( F_b = \rho_{fluid} V_{displaced} g \).
  3. Substitute the values into the formula: \( F_b = (1100 \text{ kg/m³}) \times (0.02 \text{ m³}) \times (9.8 \text{ m/s²}) \).
  4. Calculate the result: \( F_b = 215.6 \) N.
The buoyant force acting on the object is 215.6 N.
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Try It

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Applications

Naval Architecture: The principle is the foundation of ship and boat design. Engineers calculate the required hull volume and shape to displace enough water to support the vessel's total weight, including cargo and crew.

Submarine Technology: Submarines control their depth by altering their buoyancy. They take in water into ballast tanks to increase their overall density and sink (negative buoyancy), and expel water with compressed air to decrease density and rise (positive buoyancy).

Material Testing and Hydrometry: Archimedes' principle is used to determine the density of materials. By measuring an object's weight in air and its apparent weight when submerged in a fluid of known density, its volume and density can be calculated accurately. A hydrometer is an instrument that uses this principle to measure liquid density.

Aerospace Engineering: Lighter-than-air vehicles like hot air balloons and blimps operate on Archimedes' principle applied to air. A balloon rises because the hot, less-dense air inside it displaces a volume of colder, denser ambient air whose weight is greater than the total weight of the balloon.

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Real-World Examples

A cargo ship has a mass of 25,000 tonnes (25 × 10⁶ kg) when fully loaded. It floats in seawater with a density of 1025 kg/m³. Calculate the volume of seawater it displaces.
  1. For a floating object, the buoyant force must equal the object's weight. So, \( F_b = W_{ship} \).
  2. Write the formulas for each force: \( \rho_{seawater} V_{displaced} g = m_{ship} g \).
  3. The gravitational acceleration \( g \) cancels from both sides: \( \rho_{seawater} V_{displaced} = m_{ship} \).
  4. Rearrange to solve for the displaced volume: \( V_{displaced} = \frac{m_{ship}}{\rho_{seawater}} \).
  5. Substitute the given values: \( V_{displaced} = \frac{25 \times 10^6 \text{ kg}}{1025 \text{ kg/m³}} \).
  6. Calculate the result: \( V_{displaced} = 24,390 \text{ m³} \).
The ship displaces 24,390 cubic meters of seawater to stay afloat.
An iceberg with a density of 917 kg/m³ floats in seawater (density 1025 kg/m³). If the visible part of the iceberg above the water has a volume of 2000 m³, what is the total volume of the iceberg?
  1. First, find the fraction of the iceberg that is submerged using the density ratio: \( \frac{V_{submerged}}{V_{total}} = \frac{\rho_{ice}}{\rho_{seawater}} = \frac{917}{1025} = 0.895 \). This means 89.5% is submerged.
  2. Calculate the fraction of the iceberg that is above water: \( \frac{V_{above}}{V_{total}} = 1 - 0.895 = 0.105 \). So, 10.5% is visible.
  3. We know that this 10.5% fraction corresponds to a volume of 2000 m³. We can set up the equation: \( 0.105 \times V_{total} = 2000 \text{ m³} \).
  4. Solve for the total volume: \( V_{total} = \frac{2000 \text{ m³}}{0.105} \).
  5. Calculate the result: \( V_{total} \approx 19,050 \text{ m³} \).
The total volume of the iceberg is approximately 19,050 m³.
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Real-World Scenarios

Lake Ocean
Ocean vs. Lake
Denser salt water provides a greater buoyant force than fresh water, making it easier to float in the ocean.
W F₋
Life Vests
A life vest adds significant volume with little mass, displacing more water to create a large buoyant force that keeps a person afloat.
W F₋
Ice Cube in Water
An ice cube floats because it's less dense than water, displacing a volume of water equal to its own weight.

Swimming in the Ocean vs. a Lake: People find it easier to float in the ocean than in a freshwater lake. This is because seawater is denser than freshwater due to its salt content. According to Archimedes' principle, the denser fluid provides a greater buoyant force for the same volume of displaced water, making it easier to stay afloat.

Life Vests: A life vest works by adding a large volume for very little mass. When worn, it significantly increases the total volume of the person, which increases the volume of water they displace. This creates a buoyant force large enough to overcome the person's weight, keeping their head above water even if they are unconscious.

Ice Cubes in a Drink: An ice cube floats in a glass of water because ice is about 9% less dense than liquid water. The ice cube sinks until it has displaced a volume of water that weighs exactly as much as the entire ice cube. This is why you see approximately 90% of the ice cube submerged below the water's surface.

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Limitations and Assumptions

⚠️ The principle assumes the fluid is in a state of hydrostatic equilibrium (at rest). In a rapidly moving or accelerating fluid, other forces like drag and inertial effects become significant, and the simple buoyant force calculation may not be sufficient.
⚠️ The derivation assumes a uniform gravitational field over the volume of the object. For extremely large objects (e.g., on an astronomical scale), variations in gravity would need to be considered.
💡 For very small objects, surface tension can exert a force comparable to or greater than the buoyant force, which is not accounted for by Archimedes' principle. This is why a sewing needle can 'float' on water despite being denser.
💡 The principle assumes the fluid is incompressible (its density is constant). This is a very good approximation for liquids but less accurate for gases over large changes in altitude or pressure.

Common Mistakes

⚠️ Confusing object weight with buoyant force. A common error is to think the buoyant force depends on the object's properties (like its weight or density). Remember: The buoyant force depends ONLY on the displaced fluid's volume and density (\( \rho_{fluid} V_{displaced} g \)).
⚠️ Thinking heavy objects always sink. An object's behavior (floating or sinking) is determined by its density relative to the fluid, not its weight. A massive steel ship floats because its shape displaces a huge volume of water, making its effective density (total mass / displaced volume) less than water.
⚠️ Using inconsistent units. Ensure all quantities are in standard SI units before calculation. A frequent mistake is using density in g/cm³ while volume is in m³ or mass is in kg. Always convert density to kg/m³ (1 g/cm³ = 1000 kg/m³).
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Units and Dimensional Analysis

QuantitySymbolSI UnitDimensional Formula
Buoyant Force\( F_b \)Newton (N)\( [M][L][T]^{-2} \)
Density\( \rho \)kilogram per cubic meter (kg/m³)\( [M][L]^{-3} \)
Volume\( V \)cubic meter (m³)\( [L]^3 \)
Gravitational Acceleration\( g \)meter per second squared (m/s²)\( [L][T]^{-2} \)

Dimensional Analysis of Archimedes' Principle: We can verify that the dimensions of the right side of the formula match the dimensions of force.

\[ [F_b] = [\rho_{fluid}] [V_{displaced}] [g] \]
\[ [F_b] = ([M][L]^{-3}) \times ([L]^3) \times ([L][T]^{-2}) \]
\[ [F_b] = [M][L]^{(-3+3+1)}[T]^{-2} = [M][L][T]^{-2} \]
The resulting dimensions are those of force, confirming the consistency of the formula.
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Study Strategy

1 🧠 Grasp the Fundamentals
  • Read the DEFINITION section to understand that buoyant force equals the weight of the *displaced fluid*, not the object.
  • Visualize an object pushing fluid out of the way, and the fluid 'pushing back' with an upward force.
  • Study the KEY_FORMULAS section to learn how comparing object density (\( \rho_{object} \)) to fluid density (\( \rho_{fluid} \)) determines floating or sinking.
  • Draw a simple free-body diagram for a submerged object, showing the downward force of gravity (weight) and the upward buoyant force.
2 📝 Commit the Formula to Memory
  • Write down the primary formula for buoyant force: \( F_{buoyant} = \rho_{fluid} V_{displaced} g \). Label each variable.
  • Create flashcards for the three conditions from the KEY_FORMULAS section: Floats (\( \rho_{object} < \rho_{fluid} \)), Neutral (\( \rho_{object} = \rho_{fluid} \)), and Sinks (\( \rho_{object} > \rho_{fluid} \)).
  • Verbally explain the formula to a friend, emphasizing that buoyant force depends on the fluid's properties, not the object's weight.
  • Remember that for a floating object, the buoyant force is equal to the object's total weight.
3 ✍️ Practice with Problems
  • Start with simple problems: Calculate the buoyant force on a fully submerged cube where the volume is given.
  • Advance to problems with floating objects, where you must first calculate the submerged volume (\( V_{displaced} \)).
  • Review the COMMON_MISTAKES section. Actively check that you are using the *fluid's density* to calculate buoyant force.
  • Attempt problems where you must compare an object's weight to the buoyant force to determine if it will float or sink.
4 🌍 Connect to Real-World Physics
  • Read the APPLICATIONS section and explain how a massive steel ship (high density) can float by displacing a huge volume of water.
  • Consider the Submarine Technology example. Describe how ballast tanks alter a submarine's average density, allowing it to sink or rise.
  • Think about a hot-air balloon. Explain how Archimedes' principle applies to gases, causing the balloon to rise in cooler, denser air.
  • Find a real object at home, like an ice cube in a glass of water, and explain why it floats using the principle of density.
Master Archimedes' Principle by connecting the core concept of displaced fluid to the formula, practicing calculations, and seeing its powerful applications in the world around you.

Frequently Asked Questions

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