Physics Formulae Mechanics Newton's Third Law

Subset – Definition and Properties

Discover Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Understand for...
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Definition of Newton's Third Law

Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on a second object, the second object simultaneously exerts a force of equal magnitude and opposite direction on the first object. These two forces are known as an action-reaction pair.

A key insight of this law is that forces always occur in pairs; an isolated force cannot exist. This principle is fundamental to understanding how objects interact, from celestial bodies in orbit to the propulsion of a rocket in the vacuum of space.

Originally stated by Isaac Newton in his 1687 Principia Mathematica as "To every action there is always opposed an equal reaction," this law revolutionized the understanding of interactions. It forms the basis for the principle of conservation of momentum and is essential for analyzing systems in fields like structural engineering, collision dynamics, and propulsion.

Physical Properties

Newton's Third Law describes the fundamental nature of force interactions as paired, equal, and opposite. It is a universal law that governs how any two objects interact, regardless of their mass or motion.

PropertyDetails
NatureForces are vector quantities that always occur in pairs. An 'action' force on one object is always accompanied by a 'reaction' force of the same type on the other interacting object.
MagnitudeThe magnitude of the action force is always exactly equal to the magnitude of the reaction force. If object A exerts a force on B, then F_AB = F_BA.
DirectionThe direction of the reaction force is always exactly opposite (180 degrees) to the direction of the action force. As vectors, F_AB = -F_BA.
Action-Reaction PairsThe two forces in a pair act on two different objects. They never act on the same object and therefore never cancel each other out in a free-body diagram for a single object.
Conservation LawThis law is a direct statement of the conservation of linear momentum. For an isolated system of interacting particles, the net internal force is zero, and thus the total momentum is conserved.
Dimensional FormulaAs the law describes force, its dimensional formula is [M][L][T]^-2.
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Diagram & Visualization

A B FAB FBA FAB = -FBA
Newton's Third Law: For every action (F_AB), there is an equal and opposite reaction (F_BA).

Key Formulas

\[ \vec{F}_{AB} = -\vec{F}_{BA} \]
Newton's Third Law
\[ |\vec{F}_{AB}| = |\vec{F}_{BA}| \]
Equality of Magnitudes
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Variables and Symbols

SymbolQuantitySI UnitDescription
\(\vec{F}_{AB}\)Force on B by ANewton (N)The vector force that object A exerts on object B.
\(\vec{F}_{BA}\)Force on A by BNewton (N)The vector force that object B exerts on object A. This is the 'reaction' force to \(\vec{F}_{AB}\).
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Derivation from Conservation of Momentum

Newton's Third Law can be understood as a direct consequence of the conservation of momentum for an isolated system. Consider a system consisting of two interacting particles, A and B, with no external forces acting on them.

1. The total momentum of the isolated system is the sum of the individual momenta:

\[ \vec{p}_{sys} = \vec{p}_A + \vec{p}_B \]

2. Because the system is isolated, its total momentum is conserved, meaning its time derivative is zero.

\[ \frac{d\vec{p}_{sys}}{dt} = \frac{d\vec{p}_A}{dt} + \frac{d\vec{p}_B}{dt} = 0 \]

3. From Newton's Second Law, the rate of change of an object's momentum is equal to the net force acting on it (\(\vec{F}_{net} = d\vec{p}/dt\)). The only force on particle A is from B (\(\vec{F}_{BA}\)), and the only force on particle B is from A (\(\vec{F}_{AB}\)).

\[ \vec{F}_{BA} + \vec{F}_{AB} = 0 \]

4. Rearranging the equation yields Newton's Third Law.

\[ \vec{F}_{AB} = -\vec{F}_{BA} \]
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Types & Special Cases

Newton's Third Law is a universal principle that does not have different types or special cases. Instead, it is applied consistently across various scenarios involving different kinds of forces.

Type / CaseDescriptionWhen to Use
Contact ForcesForces that act at the point of physical contact between two objects. The action-reaction pair consists of the contact forces exerted by each object on the other.Analyzing scenarios like pushing a box (normal force), friction between surfaces, tension in a rope, or collisions between objects.
Non-Contact ForcesForces that act over a distance without direct physical contact. The action-reaction pair still exists between the two interacting objects.Analyzing gravitational attraction (e.g., Earth and Moon), electrostatic forces between charges, or magnetic forces between magnets or currents.
Static vs. Dynamic SystemsThe law applies equally whether the objects are at rest (static) or in motion (dynamic). The equality of action-reaction forces holds true at every instant in time.Used in both statics problems (e.g., a book resting on a table) and dynamics problems (e.g., a rocket expelling gas to accelerate).
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Worked Example (Numerical)

Object A exerts a force of \(\vec{F}_{AB} = (15\hat{i} - 20\hat{j} + 5\hat{k})\) N on Object B. What is the force exerted by Object B on Object A?
  1. Recall Newton's Third Law, which states that the force exerted by object B on object A is equal in magnitude and opposite in direction to the force exerted by A on B: \(\vec{F}_{BA} = -\vec{F}_{AB}\).
  2. Substitute the given force vector into the equation.
  3. Calculate the resulting vector: \(\vec{F}_{BA} = - (15\hat{i} - 20\hat{j} + 5\hat{k})\).
  4. Distribute the negative sign to find the final force vector: \(\vec{F}_{BA} = (-15\hat{i} + 20\hat{j} - 5\hat{k})\) N.
The force exerted by Object B on Object A is \(\vec{F}_{BA} = (-15\hat{i} + 20\hat{j} - 5\hat{k})\) N.
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Try It

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Applications in Science and Engineering

Transportation: Car wheels push the road backward, and the road pushes the car forward. An airplane propeller pushes air backward, and the air pushes the plane forward. A rocket expels hot gas downward, and the gas pushes the rocket upward.

Sports: A swimmer pushes water backward, and the water propels the swimmer forward. A runner's foot pushes the ground backward, and the ground pushes the runner forward, enabling motion.

Engineering: In structural design, the load of a bridge pushes down on its supports, and the supports exert an equal upward force to maintain equilibrium. The law is critical for analyzing forces in any mechanical system or structure.

Astronomy: The Earth exerts a gravitational pull on the Moon, and the Moon exerts an equal and opposite gravitational pull on the Earth. This interaction governs their orbits around a common center of mass.

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Real-World Worked Examples

A 1500 kg car moving at 20 m/s collides head-on with a 2000 kg truck moving at 15 m/s in the opposite direction. During the 0.2 s collision, they stick together. Find the force each vehicle exerts on the other and their accelerations.
  1. Find the final velocity using conservation of momentum: \(m_1 v_{1i} + m_2 v_{2i} = (m_1 + m_2)v_f\). This gives \(1500(20) + 2000(-15) = (3500)v_f\), so \(v_f = 0\) m/s.
  2. Calculate the acceleration of the car: \(a_1 = (v_f - v_{1i})/\Delta t = (0 - 20)/0.2 = -100 \text{ m/s²}\).
  3. Calculate the acceleration of the truck: \(a_2 = (v_f - v_{2i})/\Delta t = (0 - (-15))/0.2 = +75 \text{ m/s²}\).
  4. Calculate the force on the car from the truck using Newton's Second Law: \(F_{truck \rightarrow car} = m_1 a_1 = 1500(-100) = -150,000 \text{ N}\).
  5. By Newton's Third Law, the force on the truck from the car is equal and opposite: \(F_{car \rightarrow truck} = -F_{truck \rightarrow car} = +150,000 \text{ N}\).
Each vehicle exerts a force of 150,000 N on the other. The car's acceleration is -100 m/s², and the truck's acceleration is +75 m/s². The equal forces produce different accelerations due to the difference in mass.
A 10,000 kg rocket in space ejects 100 kg of fuel per second at an exhaust velocity of 3000 m/s relative to the rocket. Find the thrust force on the rocket.
  1. Identify the action-reaction pair: The rocket pushes fuel backward (action), and the fuel pushes the rocket forward (reaction).
  2. Calculate the force the rocket exerts on the fuel. This force is equal to the rate of change of the fuel's momentum: \(F_{rocket \rightarrow fuel} = v_{exhaust} \frac{dm}{dt}\).
  3. Substitute the values: \(F_{rocket \rightarrow fuel} = (3000 \text{ m/s}) \times (100 \text{ kg/s}) = 300,000 \text{ N}\) (backward).
  4. Apply Newton's Third Law. The force of the fuel on the rocket (the thrust) is equal in magnitude and opposite in direction: \(F_{thrust} = -F_{rocket \rightarrow fuel} = 300,000 \text{ N}\) (forward).
The thrust force on the rocket is 300,000 N in the forward direction.
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Everyday Scenarios

Action Reaction
Walking on the Ground
Your foot pushes backward on the ground (action), and the ground pushes you forward with an equal and opposite force (reaction).
Action Reaction
Book on a Table
The book exerts a downward force on the table (action), and the table pushes up on the book with an equal normal force (reaction).
Action Reaction
Jumping Up
You push down on the ground (action), and the ground pushes up on you with an equal force (reaction), propelling you into the air.

Walking on the Ground: Your foot pushes backward on the ground (action). The ground, through static friction, pushes forward on your foot with an equal force (reaction). This forward push from the ground is what propels you forward.

A Book on a Table: The book's weight (gravity from Earth) pulls it down, causing it to exert a downward force on the table (action). The table exerts an equal upward normal force on the book (reaction), keeping it stationary. The gravitational action-reaction pair is actually between the book and the Earth itself.

Jumping: To jump, you push down hard on the ground with your feet (action). The ground responds by pushing up on you with an equal and opposite force (reaction). If this upward force is greater than your weight, you accelerate upward into the air.

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Limitations and Scope

⚠️ Newton's Third Law assumes that forces are transmitted instantaneously between objects. This is a valid approximation in most classical mechanics problems but breaks down in systems where interaction speeds approach the speed of light, such as in electromagnetism or general relativity, where force-carrying fields have their own momentum.
💡 The law applies to real physical forces. When analyzing motion in a non-inertial (accelerating) reference frame, fictitious forces (like the Coriolis or centrifugal force) are introduced. These forces do not have action-reaction partners because they are not the result of an interaction between two objects.

Common Mistakes

⚠️ Mistake: Believing action-reaction forces cancel each other out. Truth: They can never cancel because they act on two different objects. Force cancellation can only occur when multiple forces act on the same object and their vector sum is zero.
⚠️ Mistake: Assuming the 'reaction' force happens after the 'action' force. Truth: The forces are perfectly simultaneous. 'Action' and 'reaction' are just convenient labels for the two forces that make up the interaction pair.
⚠️ Mistake: Thinking a more massive object exerts a larger force in an interaction. Truth: The magnitudes of the forces are always exactly equal. The more massive object simply experiences a smaller acceleration for the same force, according to Newton's Second Law (\(a = F/m\)).
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Units and Dimensions

The unit of force is derived from Newton's Second Law (\(F=ma\)). The dimensional formula for force is the product of the dimensions of mass and acceleration.

QuantitySymbolSI UnitDimensional Formula
Force\(F\)Newton (N)\([M][L][T]^{-2}\)

In SI base units, one Newton (N) is equivalent to one kilogram-meter per second squared (1 N = 1 kg·m/s²).

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Study Strategy

1 🧠 Grasp the Fundamentals
  • Carefully study the DEFINITION section to understand that forces always occur in simultaneous, equal, and opposite pairs.
  • Internalize the key insight that an action-reaction force pair always acts on two different objects.
  • Draw a simple diagram of a foot kicking a ball. Label the force of the foot on the ball ('action') and the force of the ball on the foot ('reaction').
  • Explain the difference between a balanced force pair (acting on one object) and an action-reaction pair (acting on two objects).
2 📝 Commit the Formula to Memory
  • Write the conceptual statement 'For every action, there is an equal and opposite reaction' ten times.
  • Verbally recite the law's definition, emphasizing the words 'equal magnitude' and 'opposite direction'.
  • Create a flashcard with the formal expression F_AB = -F_BA on one side and a clear explanation on the other.
  • Teach the concept to someone else, using a simple analogy like pushing off a wall to explain the interaction.
3 ✍️ Practice with Problems
  • Review the COMMON_MISTAKES section. Write a sentence explaining why action-reaction forces can never cancel each other out.
  • Address the misconception about timing. Confirm your understanding that the 'action' and 'reaction' forces happen at the exact same instant.
  • Solve a problem where you must draw free-body diagrams for two interacting objects, like a horse pulling a cart, carefully labeling the action-reaction pair.
  • For a given scenario, like a cannon firing a cannonball, identify all action-reaction pairs present in the system.
4 🌍 Connect to Real-World Physics
  • Analyze the transportation examples in the APPLICATIONS section. For a car, identify the action (tires on road) and reaction (road on tires).
  • Choose a sports example from the APPLICATIONS section, like a swimmer, and describe how the law enables their movement through the water.
  • Find a new example of the law in your daily life, such as jumping. Identify the action (you push on the Earth) and the reaction (the Earth pushes on you).
  • Watch a video of a rocket launch. Pause and explain to yourself how the expulsion of gas downwards provides the upward thrust, citing Newton's Third Law.
Master Newton's Third Law by understanding its core pairing principle, practicing with distinct objects, and observing its constant presence in the world around you.

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