Physics Formulae Electricity Work Of Electric Force

Subset – Definition and Properties

Calculate the energy transferred as a charged particle moves through an electric field. The Work of Electric Force formu...

Definition of Work of Electric Force

Work of electric force describes the energy transfer that occurs when a charged particle moves through an electric field. When an electric field exerts a force on a charge, and that charge moves through space, work is done—energy is either gained or lost by the charge. This work is path-independent for uniform fields and depends only on the initial and final positions. Positive work means the electric field does work on the charge (increasing its kinetic energy), while negative work means the charge does work against the field (decreasing its kinetic energy). This concept is fundamental to understanding capacitors, particle accelerators, lightning, and all electrical energy storage and conversion devices. The work-energy relationship in electrostatics forms the basis for electric potential and voltage concepts.

Historical Context: The concept evolved from the work of pioneers like Benjamin Franklin (1740s) on electrical action, Charles-Augustin Coulomb (1780s) who quantified electrical forces, Alessandro Volta (1800) who demonstrated electrical energy storage, and James Joule (1840s) who established the principle of energy conservation.

Physical Properties

The work done by the electric force is a scalar quantity representing the energy transferred when a charge moves within an electric field. It is fundamental for understanding changes in kinetic and potential energy in electrostatic systems.

PropertyDetails
NatureWork is a scalar quantity. It has magnitude but no direction. Its sign indicates whether energy is transferred to the charge (positive work) or from the charge (negative work) by the field.
SI UnitsThe standard unit for work is the Joule (J). One joule is the work done when a force of one newton displaces an object by one meter.
Governing FactorsThe magnitude of work depends on the magnitude of the charge (q), the strength of the electric field (E), and the component of the displacement (d) parallel to the field.
ConservationThe electrostatic force is a conservative force. This means the work done in moving a charge between two points is independent of the path taken and equals the negative change in electric potential energy (W = -ΔU).
Dimensional Formula[M L<sup>2</sup> T<sup>-2</sup>]. This is the dimension of energy.
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Diagram & Visualization

E A B d + q F Work: W = F · d
Work done (W) by the electric force (F) on a charge (q) moving a distance (d) in a uniform electric field (E).
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Key Formulas

\[ W_{MN} = qE(x_M - x_N) \]
Work in a uniform electric field along one dimension
\[ W = \vec{F} \cdot \vec{d} = qE d \cos\theta \]
General definition of work as a dot product
\[ W = -\Delta U = -(U_N - U_M) \]
Work as the negative change in electric potential energy
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Variables

SymbolQuantitySI UnitDescription
\( W_{MN} \)WorkJoule (J)Work done by the electric force as a charge moves from point M to N.
\( q \)Electric ChargeCoulomb (C)The magnitude of the electric charge experiencing the force.
\( E \)Electric Field StrengthNewton per Coulomb (N/C) or Volt per meter (V/m)The strength of the uniform electric field.
\( x_M, x_N \)Positionmeter (m)Initial and final positions of the charge along the direction of the electric field.
\( \vec{d} \)Displacement Vectormeter (m)The displacement vector of the charge from its initial to final position.
\( \theta \)Angleradians (rad) or degrees (°)The angle between the electric force vector and the displacement vector.
\( U \)Electric Potential EnergyJoule (J)The potential energy of a charge due to its position in an electric field.
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Derivation

The work done by any force \( \vec{F} \) on an object that undergoes a displacement \( d\vec{r} \) is defined by the line integral from an initial point M to a final point N.

\[ W = \int_M^N \vec{F} \cdot d\vec{r} \]

In electrostatics, the force exerted by an electric field \( \vec{E} \) on a charge \( q \) is given by \( \vec{F} = q\vec{E} \). Substituting this into the work definition:

\[ W = \int_M^N (q\vec{E}) \cdot d\vec{r} \]

For a special case of a uniform electric field, \( \vec{E} \) is constant in both magnitude and direction. We can align our coordinate system such that \( \vec{E} \) points along the x-axis, so \( \vec{E} = E\hat{i} \). The integral simplifies because \( q \) and \( \vec{E} \) can be taken outside the integral.

\[ W = q\vec{E} \cdot \int_M^N d\vec{r} = q\vec{E} \cdot (\vec{r}_N - \vec{r}_M) \]

Let the initial position be \( \vec{r}_M = x_M \hat{i} + y_M \hat{j} \) and the final position be \( \vec{r}_N = x_N \hat{i} + y_N \hat{j} \). The dot product becomes:

\[ W = q(E\hat{i}) \cdot ((x_N - x_M)\hat{i} + (y_N - y_M)\hat{j}) = qE(x_N - x_M) \]

The formula from the HTML uses the convention \( W_{MN} = qE(x_M - x_N) \), which defines the work done by the field as the charge moves from M to N. This implies a coordinate system where displacement in the direction of the field results in positive work. This shows that for a uniform field, the work done is independent of the path taken and depends only on the displacement component parallel to the field.

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Types & Special Cases

The method for calculating the work done by the electric force depends on the characteristics of the electric field and the information provided about the system.

Type / CaseDescriptionWhen to Use
Work in a Uniform FieldThe electric field is constant in both magnitude and direction. Work is calculated as W = qEd cos(θ), where θ is the angle between the field and displacement.Ideal for problems involving parallel-plate capacitors or any situation where the electric field is explicitly stated as uniform.
Work in a Non-Uniform FieldThe electric field strength and/or direction changes with position. Work is found by integrating the force over the path: W = ∫ qE · dl.Required for fields around point charges or other complex charge distributions where the field is not constant.
Work and Electric PotentialWork is expressed as the product of the charge and the potential difference: W = -qΔV = q(V_initial - V_final). This is a general and often simpler method.Extremely useful when the electric potential at the start and end points is known, as it avoids direct calculation with fields and paths.
Work along an Equipotential PathZero work is done by the electric force when a charge moves along a path where the electric potential is constant (an equipotential line or surface).This is a specific case where displacement is always perpendicular to the electric field, so W = 0.
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Worked Example

Given a uniform electric field with strength E = 400 N/C pointing in the positive x-direction. A charge q = +5 μC is moved from an initial position to a final position. Calculate the work done by the electric field for the following displacements: (a) 10 cm in the positive x-direction, (b) 10 cm in the negative x-direction, (c) 10 cm in the positive y-direction.
  1. <b>Part (a): Motion parallel to the field.</b> The displacement is in the same direction as the force. The angle θ is 0°. The displacement in the field's direction is \( \Delta x = +0.10 \) m. We use the formula \( W = qEd \cos\theta \).
  2. \( W = (5 \times 10^{-6} \text{ C})(400 \text{ N/C})(0.10 \text{ m}) \cos(0°) = 2.0 \times 10^{-4} \text{ J} \). The work is positive.
  3. <b>Part (b): Motion anti-parallel to the field.</b> The displacement is opposite to the force. The angle θ is 180°. The displacement in the field's direction is \( \Delta x = -0.10 \) m.
  4. \( W = (5 \times 10^{-6} \text{ C})(400 \text{ N/C})(0.10 \text{ m}) \cos(180°) = -2.0 \times 10^{-4} \text{ J} \). The work is negative.
  5. <b>Part (c): Motion perpendicular to the field.</b> The displacement is perpendicular to the force. The angle θ is 90°. There is no displacement component in the field's direction.
  6. \( W = (5 \times 10^{-6} \text{ C})(400 \text{ N/C})(0.10 \text{ m}) \cos(90°) = 0 \text{ J} \). No work is done.
The work done is (a) +2.0 x 10⁻⁴ J, (b) -2.0 x 10⁻⁴ J, and (c) 0 J.
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Try It

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Applications

Energy Storage Devices: The work done to move charges against an electric field is the principle behind storing energy in batteries and capacitors. Charging a battery involves doing work to separate charges, storing potential energy that can be released later.

Particle Accelerators: Devices like linear accelerators and cyclotrons use strong electric fields to do positive work on charged particles (like protons or electrons), accelerating them to extremely high speeds for scientific research and medical applications like radiation therapy.

Electronic Displays: Older Cathode Ray Tube (CRT) televisions and monitors used electric fields to do work on a beam of electrons, deflecting them precisely to create an image on a phosphorescent screen.

Medical Devices: Defibrillators use the energy stored in a capacitor to deliver a large amount of charge through the heart, with the electric field doing work to restore a normal rhythm. X-ray tubes accelerate electrons using an electric field to produce X-rays upon impact with a target.

Industrial Processes: Electroplating uses an electric field to do work on metal ions in a solution, causing them to deposit onto an object. Electrostatic precipitators use electric work to remove soot and ash particles from industrial exhaust.

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Real-World Examples

A parallel plate capacitor has plates separated by 5 cm with a uniform electric field of 2000 N/C. Calculate the work done by the electric force when a +3 μC charge moves: (a) from the positive to the negative plate, (b) from the negative to the positive plate, and (c) parallel to the plates for 3 cm.
  1. <b>Part (a): Positive to negative plate.</b> The charge moves with the field. Displacement \( x_M - x_N = 0.05 \) m.
  2. \[ W_{MN} = qE(x_M - x_N) = (3 \times 10^{-6})(2000)(0.05) = 3.0 \times 10^{-4} \text{ J} \]
  3. <b>Part (b): Negative to positive plate.</b> The charge moves against the field. Displacement \( x_M - x_N = -0.05 \) m.
  4. \[ W_{MN} = qE(x_M - x_N) = (3 \times 10^{-6})(2000)(-0.05) = -3.0 \times 10^{-4} \text{ J} \]
  5. <b>Part (c): Parallel to plates.</b> The motion is perpendicular to the field. Displacement in the field direction is zero.
  6. \[ W_{MN} = qE(0) = 0 \text{ J} \]
The work done is (a) +0.3 mJ, (b) -0.3 mJ, and (c) 0 J.
An electron (q = -1.6×10⁻¹⁹ C, m = 9.1×10⁻³¹ kg) starts from rest and accelerates through a uniform electric field of 500 N/C for a distance of 2 cm. Calculate the final velocity of the electron.
  1. <b>Step 1: Calculate the work done.</b> The force on the electron is in the direction of motion (opposite to the E-field). Thus, the work done by the field is positive.
  2. \[ W = |qE|d = (1.6 \times 10^{-19})(500)(0.02) = 1.6 \times 10^{-18} \text{ J} \]
  3. <b>Step 2: Apply the Work-Energy Theorem.</b> The work done equals the change in kinetic energy. Since it starts from rest, \( KE_i = 0 \).
  4. \[ W = \Delta KE = KE_f - KE_i = \frac{1}{2}mv_f^2 \]
  5. <b>Step 3: Solve for final velocity \( v_f \).</b>
  6. \[ v_f = \sqrt{\frac{2W}{m}} = \sqrt{\frac{2(1.6 \times 10^{-18})}{9.1 \times 10^{-31}}} \]
  7. \[ v_f \approx 1.87 \times 10^6 \text{ m/s} \]
The final velocity of the electron is approximately 1.87 x 10⁶ m/s.
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Real-World Scenarios

Lightning Strike
The immense electric field between a cloud and the ground does work on air molecules, creating the massive energy discharge of lightning.
Battery Circuit
A battery's internal electric field does work on electrons, pushing them through a circuit to transfer energy and power a device.
- + - + - + - + - +
Inkjet Deflection
An electric field does work on a charged ink droplet, changing its kinetic energy and deflecting its path to a precise location on paper.

Lightning Strike: During a thunderstorm, a massive potential difference builds up between clouds and the ground, creating a powerful electric field. This field does an immense amount of work on free charges in the air, accelerating them and causing a cascade of collisions that ionize the air, forming a conductive plasma channel. The resulting rapid discharge is a lightning bolt, where the work done by the field is converted into light, heat, and sound.

Battery Powering a Device: Inside a battery, a chemical reaction establishes an electric field. When you connect a device, this field does work on electrons in the circuit, pushing them from the negative to the positive terminal. This work transfers potential energy from the battery to the electrons, which then deliver that energy to the components of the device, powering a light bulb or a smartphone.

Inkjet Printer: In some inkjet printers, tiny droplets of ink are given an electric charge. As they pass through a uniform electric field between two plates, the field does work on them, deflecting their path. By precisely controlling the field strength, the printer can direct each droplet to a specific location on the paper, forming letters and images.

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Limitations

⚠️ The formulas presented, particularly the path-independent nature (W = qEd), are valid only for static electric fields (electrostatics). The electrostatic field is a conservative field.
⚠️ The principle of path independence breaks down in the presence of a time-varying magnetic field. A changing magnetic field induces a non-conservative electric field, where the work done on a charge moving in a closed loop is not zero. This is the basis of electromagnetic induction.
💡 These formulas assume the charge is moving in a vacuum. In a material medium, other forces like drag or friction may be present, and the net work done on the particle will include contributions from these non-conservative forces.

Common Mistakes

⚠️ Sign Convention Errors: Forgetting to account for the sign of the charge (q) and the direction of motion relative to the field. A positive charge moving with the field has positive work done on it, while a negative charge (like an electron) moving with the field has negative work done on it.
⚠️ Using Total Distance Instead of Parallel Component: The work done by a uniform electric field depends only on the displacement component that is parallel to the field lines. Motion perpendicular to the field does no work. Using the total path length for a path at an angle to the field will give an incorrect answer.
⚠️ Confusing Work and Potential Energy: The work done by the conservative electric force is equal to the *negative* change in potential energy (\( W = -\Delta U \)). A common mistake is to equate work with the positive change, which reverses the energy accounting.
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Units and Dimensions

Dimensional analysis ensures the consistency of physics equations. The base dimensions used are Mass (M), Length (L), Time (T), and Electric Current (I).

QuantitySymbolSI UnitDimensional Formula
Work / EnergyW, UJoule (J)[M L² T⁻²]
Electric ChargeqCoulomb (C)[I T]
Electric FieldEN/C or V/m[M L T⁻³ I⁻¹]
Displacementd, xmeter (m)[L]
ForceFNewton (N)[M L T⁻²]
Electric PotentialVVolt (V)[M L² T⁻³ I⁻¹]

Dimensional Check: Checking the formula \( W = qEd \):
\( [W] = [q] [E] [d] \)
\( [M L^2 T^{-2}] = ([I T]) ([M L T^{-3} I^{-1}]) ([L]) \)
\( [M L^2 T^{-2}] = [M L^2 T^{-2}] \). The dimensions match, confirming the formula's consistency.

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Study Strategy

1 🧠 Grasp the Fundamentals
  • Read the DEFINITION section to understand work as energy transfer when a charge moves in an electric field.
  • Focus on the key concept that work is path-independent in uniform fields, depending only on start and end points.
  • Visualize the core relationship: the electric field (E) exerts a force (F) on a charge (q), causing work to be done.
  • Distinguish between positive work (field assists motion, charge gains kinetic energy) and negative work (field opposes motion).
2 📝 Commit the Formula to Memory
  • Memorize the general formula for work: W = Fd cos(θ), where θ is the angle between force and displacement.
  • Learn the specific formula for a uniform field: W = qEd, where d is the displacement parallel to the field.
  • Connect work to the change in electric potential energy: W = -ΔU_E.
  • Relate work to electric potential difference (voltage): W = qV, which simplifies many problems.
3 ✍️ Practice with Problems
  • Start with simple scenarios: a proton moving with the field, then an electron moving against the field.
  • Review the COMMON_MISTAKES section to actively avoid sign convention errors with positive vs. negative charges.
  • Practice problems where movement is at an angle, ensuring you use only the displacement component parallel to the field.
  • Solve a problem, then check it against a Worked Example to compare your method and identify any gaps in understanding.
4 🌍 Connect to Real-World Physics
  • Study the APPLICATIONS section to see how work is done to store energy in batteries and capacitors.
  • Visualize how particle accelerators use electric fields to do positive work, accelerating particles to incredible speeds.
  • Relate the concept to something familiar, like the work done by gravity as a ball falls or is lifted.
  • Think about how work done by the electric field inside a television or monitor guides electrons to create an image.
Master the work of electric force by understanding it as energy transfer, practicing sign conventions, and connecting it to real-world tech like batteries.

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